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How can I write a query to return a count for each day ongoing with date columns vertical?

Hello, I'm trying to write a query that will return the number of tickets each person works, each day. I'd like to have the names going down the left side, and each day's date going across the top, with the count for each person below the date. I'd like for it to run across like this for 1 rolling year, if possible. It should look like below (sample data is below this example):
         8/1/2016     8/2/2016    etc....
Bob        3                    1          etc...
Sally       2                    1          etc...
John       1                    2          etc...

Each number is a count of records closed that day by the user, a sample of the data would look like this

ID UserName DateTicketClosed
1    Bob              8/1/2016
2    Bob              8/1/2016
3    Bob              8/1/2016
4    Bob              8/2/2016
5     Sally            8/1/2016
6     Sally            8/1/2016
7     Sally            8/2/2016
8     John            8/1/2016
9     John            8/2/2016
10   John            8/2/2016

Could someone assist?
0
earwig75
Asked:
earwig75
1 Solution
 
gplanaCommented:
SQL as a database language standard doesn't have such feature, as its goal is to retrieve data organized by rows. So any resulting record is on a row, and columns are used for attributes (also called fields or even columns).

However, you can reach this by using some tools like Oracle Reports, which is more related on how to present this information to user.

Hope it helps. Regards.
0
 
SharathData EngineerCommented:
Can be done. Let me know if you are still looking for a sql query.
0
 
PortletPaulCommented:
"PIVOT"
is the T-SQL feature provided for this type of output

or: use of case expressions, aggregate functions and a group by
0

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