Improve company productivity with a Business Account.Sign Up

x
  • Status: Solved
  • Priority: Medium
  • Security: Public
  • Views: 149
  • Last Modified:

has22 challenge

Hi,

I am working on below challenge

http://codingbat.com/prob/p121853
I wrote my code as below
public boolean has22(int[] nums) {
 
  
  boolean result=false;

  int sum=0;
  for(int n:nums){
   if(n==2)
   result=true;
  
  }
   return result;




}

Open in new window






I am not passing all tests

Expected      Run            
has22([1, 2, 2]) → true      true      OK      
has22([1, 2, 1, 2]) → false      true      X      
has22([2, 1, 2]) → false      true      X      
has22([2, 2, 1, 2]) → true      true      OK      
has22([1, 3, 2]) → false      true      X      
has22([1, 3, 2, 2]) → true      true      OK      
has22([2, 3, 2, 2]) → true      true      OK      
has22([4, 2, 4, 2, 2, 5]) → true      true      OK      
has22([1, 2]) → false      true      X      
has22([2, 2]) → true      true      OK      
has22([2]) → false      true      X      
has22([]) → false      false      OK      
has22([3, 3, 2, 2]) → true      true      OK      
has22([5, 2, 5, 2]) → false      true      X      
other tests
X      


How to improve my design, approach, code? please advise
0
gudii9
Asked:
gudii9
  • 4
  • 4
  • 3
2 Solutions
 
CPColinSenior Java ArchitectCommented:
You're supposed to return true only when there's more than one 2 in a row. Your code is returning true when there's a 2 anywhere.
0
 
krakatoaCommented:
public boolean has22(int[] nums) {
  
  for(int y=0;y<nums.length-1;y++){xxxxxxxxxxx){return true;}}
  return false;
}

Open in new window


... what do you insert instead of the xs??
0
 
gudii9Author Commented:
let me check
0
What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

 
krakatoaCommented:
Is this snippet relevant or not in this question:

if(nums[y]==2&&nums[y+1]==2)

Open in new window

0
 
gudii9Author Commented:
public boolean has22(int[] nums) {
 
  
  boolean result=false;

  int sum=0;
  int len=nums.length;
  for(int i=0;i<len-1;i++){
   if(nums[i]==2&&nums[i+1]==2)
   result=true;
  
  }
   return result;




}

Open in new window


above passed all tests? any improvements, suggestions, comments?
0
 
CPColinSenior Java ArchitectCommented:
You could return true as soon as you find two 2's next to each other and save a little processing time. (If you have an array that's a thousand elements long and the first two elements are 2's, you don't need to check the rest of the array, since you already know you'll be returning true.)
0
 
gudii9Author Commented:
You could return true as soon as you find two 2's next to each other and save a little processing time.

how to do this?
0
 
CPColinSenior Java ArchitectCommented:
return true;
0
 
gudii9Author Commented:
public boolean has22(int[] nums) {
 
  
 // boolean result=false;

  int sum=0;
  int len=nums.length;
  for(int i=0;i<len-1;i++){
   if(nums[i]==2&&nums[i+1]==2)
  return true;
  
  }
  // return result;
return false;



}

Open in new window


i see . this is very powerful to use return here.
0
 
CPColinSenior Java ArchitectCommented:
Yep! You can't always break out of a loop early or return from a loop early, but it can be nice, when you can.
0
 
krakatoaCommented:
i see . this is very powerful to use return here.

I ALREADY posted code with this return clause in it !

Did you even *look* at that ???

You ARE a troll, are you not ????
1
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

Featured Post

What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

  • 4
  • 4
  • 3
Tackle projects and never again get stuck behind a technical roadblock.
Join Now