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Solved
T-SQL - Get Same Address1 with Different Address2
Posted on 2016-08-03
Hi Experts!
Have the following data and need a query to find the Pid that has same
Address1, but different Address2.
Query should RETURN 1, 4, and 5 -- this is for SQL Server 2012
PiD Address1 Address2
----- ----------------- --------------
1 123 ABC St Suite 201
1 123 XYZ St Suite 201
1 123 Cookie St Suite 201
1 123 ABC St Suite 201
1 123 ABC St Suite 301
2 457 Marvel St Suite 1001
2 1 DownTown Lane
3 2 Busy Rd Apt 2001
3 2 Busy Ave Apt 20
3 2 Busy Ave Apt 20
4 10 CutOver Lane Suite 201
4 10 CutOver Lane Suite 301
4 10 CutOver Lane Suite 401
5 10 CutOver Lane Suite 201
5 10 CutOver Lane Suite 301
TIA!
Have the following data and need a query to find the Pid that has same
Address1, but different Address2.
Query should RETURN 1, 4, and 5 -- this is for SQL Server 2012
PiD Address1 Address2
----- ----------------- --------------
1 123 ABC St Suite 201
1 123 XYZ St Suite 201
1 123 Cookie St Suite 201
1 123 ABC St Suite 201
1 123 ABC St Suite 301
2 457 Marvel St Suite 1001
2 1 DownTown Lane
3 2 Busy Rd Apt 2001
3 2 Busy Ave Apt 20
3 2 Busy Ave Apt 20
4 10 CutOver Lane Suite 201
4 10 CutOver Lane Suite 301
4 10 CutOver Lane Suite 401
5 10 CutOver Lane Suite 201
5 10 CutOver Lane Suite 301
DECLARE @PersonAddress TABLE
(
PiD int,
Address1 varchar(50),
Address2 varchar(50)
)
INSERT INTO @PersonAddress (PiD, Address1, Address2)
SELECT 1, '123 ABC St', 'Suite 201' UNION ALL
SELECT 1, '123 XYZ St', 'Suite 201' UNION ALL
SELECT 1, '123 Cookie St', 'Suite 201' UNION ALL
SELECT 1, '123 ABC St', 'Suite 201' UNION ALL
SELECT 1, '123 ABC St', 'Suite 301' UNION ALL
SELECT 2, '457 Marvel St', 'Suite 1001' UNION ALL
SELECT 2, '1 DownTown Lane', '' UNION ALL
SELECT 3, '2 Busy Rd', 'Apt 2001' UNION ALL
SELECT 3, '2 Busy Ave', 'Apt 20' UNION ALL
SELECT 3, '2 Busy Ave', 'Apt 20' UNION ALL
SELECT 4, '10 CutOver Lane', 'Suite 201' UNION ALL
SELECT 4, '10 CutOver Lane', 'Suite 301' UNION ALL
SELECT 4, '10 CutOver Lane', 'Suite 401' UNION ALL
SELECT 5, '10 CutOver Lane', 'Suite 201' UNION ALL
SELECT 5, '10 CutOver Lane', 'Suite 301'
TIA!
-
4
2
6 Comments
Active 1 day ago
try this:
select a.PiD from
(
Select PiD, Address1
from @PersonAddress
group by PiD, Address1
having count(Address1) > 1
) a inner join
@PersonAddress b on a.PiD = b.PiD and a.Address1 = b.Address1
group by a.PiD
having count(distinct b.Address2) > 1
Ryan,
Here's an example where it shouldn't return the PiD,but it did:
Here's an example where it shouldn't return the PiD,but it did:
DECLARE @PersonAddress TABLE
(
PiD int,
Address1 varchar(50),
Address2 varchar(50)
)
INSERT INTO @PersonAddress (PiD, Address1, Address2)
SELECT 30, '73-345 Power Pl', 'Suite 200' UNION ALL
SELECT 30, '73-345 Power Pl', 'Suite 200' UNION ALL
SELECT 30, '73-345 Power Pl', 'Suite 200' UNION ALL
SELECT 30, '73-345 Power Pl', 'Suite 200' UNION ALL
SELECT 30, '73-345 Power Pl', 'Suite 200' UNION ALL
SELECT 30, '73-345 Power Pl', 'Suite 200' UNION ALL
SELECT 30, '75-240 Krazy Dr', 'Suite 6B' UNION ALL
SELECT 30, '75-240 Krazy Dr', 'Suite 6B' UNION ALL
SELECT 30, '75-240 Krazy Dr', 'Suite 6B' UNION ALL
SELECT 30, '75-240 Krazy Dr', 'Suite 6B' UNION ALL
SELECT 30, '75-240 Krazy Dr', 'Suite 6B' UNION ALL
SELECT 30, '75-240 Krazy Dr', 'Suite 6B' UNION ALL
SELECT 30, '98-151 Saint St', 'Suite 142' UNION ALL
SELECT 30, '98-151 Saint St', 'Suite 142' UNION ALL
SELECT 30, '98-151 Saint St', 'Suite 142' UNION ALL
SELECT 30, '98-151 Saint St', 'Suite 142' UNION ALL
SELECT 30, '98-151 Saint St', 'Suite 142'
Active 1 day ago
oppps, you may try this instead:
select a.PiD from
(
select a.PiD, a.Address1, b.Address2 from
(
Select PiD, Address1
from @PersonAddress
group by PiD, Address1
having count(Address1) > 1
) a inner join
@PersonAddress b on a.PiD = b.PiD and a.Address1 = b.Address1
group by a.PiD, a.Address1, b.Address2
) a
group by a.PiD, a.Address1
having count(a.PiD) > 1
order by a.PiD
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