Get array elements with condition in javascript

Angular 1.x or Angular 2?

Why not use ng-show / ng-hide

https://docs.angularjs.org/api/ng/directive/ngShow
https://docs.angularjs.org/api/ng/directive/ngHide

Without knowing the specifics of your code and the conditions you want to hide show on - cannot provide a code solution - however if you do  something like this

<ul>
  <li ng-repeat="item in items" ngShow="item.value==condition">{{item.option}}</li>
</ul>

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Or if you need more control over the condition

<ul>
  <li ng-repeat="item in items" ngShow="showItem(item)">{{item.option}}</li>
</ul>

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And the in your controller you return true or false from the showitem function based on the criteria you want to show / hide on

Thank you for your response.I am using Angular 1.5 . Could you please elaborate the above explanation.

My requirement is , In the pen I took array of elements in javascript to show in menu (In reality the  Menu items will be New, Delete, Update, Print etc.) . From API I get some data and based on condition the menu items will change.

Ex:

If condition1==true
showMenuItems=["NEw", "Print"];

If condition2==true
showMenuItems=["Update","Print"]

If condition3==true
showMenuItems=["New"," Delete", "Update", "Print"]

My question is should I take 3 separate arrays as I have 3 conditions with different array of elements or should I add / remove elements in the array based on condition . It would be great if you provide sample code.

Thanks in advance

Hi Experts,

Looking for some help on the above issue.

var conditions = {
      {         Option: “New”,
                          Condition: 1,
            Option: “Print”,
                          Condition: 1,
      },
      {         Option: “Update”,
                          Condition: 2,
            Option: “Print”,
                          Condition: 2,
      },
}
Var filterCondition = 1;
You can filter the JSON data as
Var showMenuItems  = Conditions.filter(function(item){ return item.Condition == filterCondition; })

Thank you

You are welcome.