Solved

C# - Read / Write Data to App.Config file in a specific directory

Posted on 2016-08-03
9
99 Views
Last Modified: 2016-08-05
I have an app.config file which I'm storing in a different directory structure.  Is it possible to Read / Write to that config file?

Read
 key = ConfigurationManager.AppSettings[ReportName];

Open in new window

Write
config.AppSettings.Settings.Add("key1", "value");

Open in new window

MyDir
--App.Config
MyApp
--MyApp.exe
--App.config

I want to access App.Config in "MyDir" Directory
0
Comment
Question by:CipherIS
  • 6
  • 3
9 Comments
 
LVL 62

Expert Comment

by:Fernando Soto
Comment Utility
Hi ;

You should be able to get an instance of the configuration object and use that to access the section of the config file. Please see this Microsoft doc which has an example. ConfigurationManager.OpenMappedExeConfiguration Method (ExeConfigurationFileMap, ConfigurationUserLevel, Boolean)
0
 
LVL 1

Author Comment

by:CipherIS
Comment Utility
That is what I thought.  I tried that.

 Configuration config = ConfigurationManager.OpenExeConfiguration(sConfig);

key = config.AppSettings[ReportName];

Open in new window

However for "config.AppSettings" I receive an error

ConfigurationElement.this[Configuration.Property] is inaccessible due to its protection level.

For sConfig I'm passing in like "C:\MyDir\App.config".
0
 
LVL 1

Author Comment

by:CipherIS
Comment Utility
Below is my Code.  Still receiving an error.
string key = string.Empty;
string sConfig = string.Empty;

Files files = new Files();
sConfig = Path.Combine( files.ReturnSaveLocation(), @"App.Config");

Configuration config = ConfigurationManager.OpenExeConfiguration(sConfig);
ExeConfigurationFileMap configFile = new ExeConfigurationFileMap();
configFile.ExeConfigFilename = sConfig;
Configuration mConfig = ConfigurationManager.OpenMappedExeConfiguration(configFile, ConfigurationUserLevel.None, true);

string s = aem.ReportName;
key = mConfig.AppSettings[s];  //Receiving error here.  Inaccessible due to protection level.

Open in new window

0
 
LVL 1

Author Comment

by:CipherIS
Comment Utility
Having issues with the app.config.  Looking at just reading/writing to XML.

Is there a way to read write to XML so I can have similar result?

<key=1>  <value=123>
<key=2>  <value=abc>

I want to be able to check to see if key 1 exists and if it doesn't add it to the XML file along with it't value and so on.

Thanks.
0
How to run any project with ease

Manage projects of all sizes how you want. Great for personal to-do lists, project milestones, team priorities and launch plans.
- Combine task lists, docs, spreadsheets, and chat in one
- View and edit from mobile/offline
- Cut down on emails

 
LVL 1

Author Comment

by:CipherIS
Comment Utility
Hope this makes sense.  Check the xml for Key value 3.
<?xml version="1.0" encoding="utf-8"?>
<Reports>
    <report>
        <key>1</>
        <value>123</value>
    </report>
    <report>
        <key>2</>
        <value>abc</value>
    <report>
</Reports>

Open in new window

if it doesn't exist then add it.
<?xml version="1.0" encoding="utf-8"?>
<Reports>
    <report>
        <key>1</>
        <value>123</value>
    </report>
    <report>
        <key>2</>
        <value>abc</value>
    </report>
    <report>
        <key>3</>
        <value>12ab</value>
    </report>
</Reports>

Open in new window

If it does exist then update it
<?xml version="1.0" encoding="utf-8"?>
<Reports>
    <report>
        <key>1</>
        <value>123</value>
    </report>
    <report>
        <key>2</>
        <value>abc</value>
    </report>
    <report>
        <key>3</>
        <value>ab12</value>
    </report>
</Reports>

Open in new window

0
 
LVL 1

Author Comment

by:CipherIS
Comment Utility
This is what I was able to come up with so far.
    public class XML
    {
        public string ReadXML(string key)
        {
			bool found = false

			return found;
        }

        public bool WriteXML(string sKey, string sValue)
        {
            Files file = new Files();
            string saveLocation = file.ReturnSaveLocation();
            string xml = string.Empty;

            xml = Path.Combine(saveLocation, "Reports.xml");

            XmlDocument doc = new XmlDataDocument();
            doc.Load(xml);

            XmlNamespaceManager namespaces = new XmlNamespaceManager(doc.NameTable);
            namespaces.AddNamespace("Reports", "http://www.w3.org/2001/XMLSchema");

            XmlNode nextNode = doc.SelectSingleNode("/Reports", namespaces);

            XmlElement report = doc.CreateElement("Export");

            XmlElement key = doc.CreateElement("Key");
            key.InnerText = sKey;

            XmlElement value = doc.CreateElement("Value");
            value.InnerText = sValue;

            nextNode.AppendChild(key);
            key.AppendChild(value);

            doc.Save(xml);

            return true;
        }
    }

Open in new window


It is inserting key and value but not correctly.  It is inserting it as

<key>1<value>123</value</key>

Can't get <report> added.  Don't know if I need to or not.  

Any suggestions?
0
 
LVL 62

Accepted Solution

by:
Fernando Soto earned 500 total points
Comment Utility
Hi CipherIS;

Here is a code snippet that will work with an XML Document. I modified the schema a little to be less verbose and simpler to modify.
using System.Xml.Linq;

// Location and name of the XML file
string filePathName = "C:\\Working Directory\\reports.xml";
// Load the XML into memory
XDocument xdoc = XDocument.Load(filePathName);
string keyToCheck = "5";
string valueToApply = "Fernando";
// Query the document
XElement result = xdoc.Root.Descendants("key")
                      .Where(k => k.Value == keyToCheck)
                      .Select(k => k)
                      .FirstOrDefault();
// Check to see if the key was found
if(result == null) {
    // Key was NOT found so add it to the document
    XElement newElement = new XElement("key", keyToCheck, new XAttribute("value", valueToApply));
    // Add it to the document
    xdoc.Root.Element( "report" ).Add( newElement );
} else {
    // Modify the value of the one it found
    result.Attribute("value").SetValue(valueToApply);
}
// Save the document back to the file system
xdoc.Save( filePathName );

Open in new window

This is what the new schema looks like
<?xml version="1.0" encoding="utf-8"?>
<Reports>
  <report>
    <key value="123">1</key>
    <key value="abc">2</key>
    <key value="12zz">3</key>
    <key value="abc123">5</key>
  </report>
</Reports>

Open in new window

0
 
LVL 1

Author Closing Comment

by:CipherIS
Comment Utility
Thanks so much.  The code is cleaner and easier to understand also.
0
 
LVL 62

Expert Comment

by:Fernando Soto
Comment Utility
Not a problem CipherIS, glad I was able to help.
0

Featured Post

Top 6 Sources for Identifying Threat Actor TTPs

Understanding your enemy is essential. These six sources will help you identify the most popular threat actor tactics, techniques, and procedures (TTPs).

Join & Write a Comment

A long time ago (May 2011), I have written an article showing you how to create a DLL using Visual Studio 2005 to be hosted in SQL Server 2005. That was valid at that time and it is still valid if you are still using these versions. You can still re…
Exception Handling is in the core of any application that is able to dignify its name. In this article, I'll guide you through the process of writing a DRY (Don't Repeat Yourself) Exception Handling mechanism, using Aspect Oriented Programming.
Get a first impression of how PRTG looks and learn how it works.   This video is a short introduction to PRTG, as an initial overview or as a quick start for new PRTG users.
This video gives you a great overview about bandwidth monitoring with SNMP and WMI with our network monitoring solution PRTG Network Monitor (https://www.paessler.com/prtg). If you're looking for how to monitor bandwidth using netflow or packet s…

772 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question

Need Help in Real-Time?

Connect with top rated Experts

11 Experts available now in Live!

Get 1:1 Help Now