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C# - Read / Write Data to App.Config file in a specific directory

Posted on 2016-08-03
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Last Modified: 2016-08-05
I have an app.config file which I'm storing in a different directory structure.  Is it possible to Read / Write to that config file?

Read
 key = ConfigurationManager.AppSettings[ReportName];

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Write
config.AppSettings.Settings.Add("key1", "value");

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MyDir
--App.Config
MyApp
--MyApp.exe
--App.config

I want to access App.Config in "MyDir" Directory
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Question by:CipherIS
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9 Comments
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 41741680
Hi ;

You should be able to get an instance of the configuration object and use that to access the section of the config file. Please see this Microsoft doc which has an example. ConfigurationManager.OpenMappedExeConfiguration Method (ExeConfigurationFileMap, ConfigurationUserLevel, Boolean)
0
 
LVL 1

Author Comment

by:CipherIS
ID: 41742507
That is what I thought.  I tried that.

 Configuration config = ConfigurationManager.OpenExeConfiguration(sConfig);

key = config.AppSettings[ReportName];

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However for "config.AppSettings" I receive an error

ConfigurationElement.this[Configuration.Property] is inaccessible due to its protection level.

For sConfig I'm passing in like "C:\MyDir\App.config".
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LVL 1

Author Comment

by:CipherIS
ID: 41742653
Below is my Code.  Still receiving an error.
string key = string.Empty;
string sConfig = string.Empty;

Files files = new Files();
sConfig = Path.Combine( files.ReturnSaveLocation(), @"App.Config");

Configuration config = ConfigurationManager.OpenExeConfiguration(sConfig);
ExeConfigurationFileMap configFile = new ExeConfigurationFileMap();
configFile.ExeConfigFilename = sConfig;
Configuration mConfig = ConfigurationManager.OpenMappedExeConfiguration(configFile, ConfigurationUserLevel.None, true);

string s = aem.ReportName;
key = mConfig.AppSettings[s];  //Receiving error here.  Inaccessible due to protection level.

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LVL 1

Author Comment

by:CipherIS
ID: 41743088
Having issues with the app.config.  Looking at just reading/writing to XML.

Is there a way to read write to XML so I can have similar result?

<key=1>  <value=123>
<key=2>  <value=abc>

I want to be able to check to see if key 1 exists and if it doesn't add it to the XML file along with it't value and so on.

Thanks.
0
 
LVL 1

Author Comment

by:CipherIS
ID: 41743170
Hope this makes sense.  Check the xml for Key value 3.
<?xml version="1.0" encoding="utf-8"?>
<Reports>
    <report>
        <key>1</>
        <value>123</value>
    </report>
    <report>
        <key>2</>
        <value>abc</value>
    <report>
</Reports>

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if it doesn't exist then add it.
<?xml version="1.0" encoding="utf-8"?>
<Reports>
    <report>
        <key>1</>
        <value>123</value>
    </report>
    <report>
        <key>2</>
        <value>abc</value>
    </report>
    <report>
        <key>3</>
        <value>12ab</value>
    </report>
</Reports>

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If it does exist then update it
<?xml version="1.0" encoding="utf-8"?>
<Reports>
    <report>
        <key>1</>
        <value>123</value>
    </report>
    <report>
        <key>2</>
        <value>abc</value>
    </report>
    <report>
        <key>3</>
        <value>ab12</value>
    </report>
</Reports>

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0
 
LVL 1

Author Comment

by:CipherIS
ID: 41743224
This is what I was able to come up with so far.
    public class XML
    {
        public string ReadXML(string key)
        {
			bool found = false

			return found;
        }

        public bool WriteXML(string sKey, string sValue)
        {
            Files file = new Files();
            string saveLocation = file.ReturnSaveLocation();
            string xml = string.Empty;

            xml = Path.Combine(saveLocation, "Reports.xml");

            XmlDocument doc = new XmlDataDocument();
            doc.Load(xml);

            XmlNamespaceManager namespaces = new XmlNamespaceManager(doc.NameTable);
            namespaces.AddNamespace("Reports", "http://www.w3.org/2001/XMLSchema");

            XmlNode nextNode = doc.SelectSingleNode("/Reports", namespaces);

            XmlElement report = doc.CreateElement("Export");

            XmlElement key = doc.CreateElement("Key");
            key.InnerText = sKey;

            XmlElement value = doc.CreateElement("Value");
            value.InnerText = sValue;

            nextNode.AppendChild(key);
            key.AppendChild(value);

            doc.Save(xml);

            return true;
        }
    }

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It is inserting key and value but not correctly.  It is inserting it as

<key>1<value>123</value</key>

Can't get <report> added.  Don't know if I need to or not.  

Any suggestions?
0
 
LVL 63

Accepted Solution

by:
Fernando Soto earned 500 total points
ID: 41743254
Hi CipherIS;

Here is a code snippet that will work with an XML Document. I modified the schema a little to be less verbose and simpler to modify.
using System.Xml.Linq;

// Location and name of the XML file
string filePathName = "C:\\Working Directory\\reports.xml";
// Load the XML into memory
XDocument xdoc = XDocument.Load(filePathName);
string keyToCheck = "5";
string valueToApply = "Fernando";
// Query the document
XElement result = xdoc.Root.Descendants("key")
                      .Where(k => k.Value == keyToCheck)
                      .Select(k => k)
                      .FirstOrDefault();
// Check to see if the key was found
if(result == null) {
    // Key was NOT found so add it to the document
    XElement newElement = new XElement("key", keyToCheck, new XAttribute("value", valueToApply));
    // Add it to the document
    xdoc.Root.Element( "report" ).Add( newElement );
} else {
    // Modify the value of the one it found
    result.Attribute("value").SetValue(valueToApply);
}
// Save the document back to the file system
xdoc.Save( filePathName );

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This is what the new schema looks like
<?xml version="1.0" encoding="utf-8"?>
<Reports>
  <report>
    <key value="123">1</key>
    <key value="abc">2</key>
    <key value="12zz">3</key>
    <key value="abc123">5</key>
  </report>
</Reports>

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0
 
LVL 1

Author Closing Comment

by:CipherIS
ID: 41743318
Thanks so much.  The code is cleaner and easier to understand also.
0
 
LVL 63

Expert Comment

by:Fernando Soto
ID: 41743365
Not a problem CipherIS, glad I was able to help.
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