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Permission from Folder

Posted on 2016-08-04
3
68 Views
Last Modified: 2016-08-04
I need help is possible save the users list with permission and a folder?


Example

Folder 1

Permissions tab
user1
user2
user3


I nee save in save in a list the name of the folder and which user are in the permissions tab
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Comment
Question by:PLCITS
3 Comments
 
LVL 12

Assisted Solution

by:Benjamin Voglar
Benjamin Voglar earned 125 total points
ID: 41742439
you can do it with powershell:

get-acl c:\it | select -expand access | ft

change c:\it with your path.

you can save the result in to a file:

get-acl c:\it | select -expand access | export-csv c:\it\list.csv
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LVL 1

Assisted Solution

by:cmil
cmil earned 125 total points
ID: 41742458
I user a powershell script for this

[cmdletbinding()]

param([Parameter(ValueFromPipeline=$True,
    ValueFromPipelineByPropertyName=$True)]$Computer = '[b][u]COMPUTER NAME HERE[/u][/b]') 

$shares = gwmi -Class win32_share -ComputerName $computer | select -ExpandProperty Name 
 
foreach ($share in $shares) { 
    $acl = $null 
    Write-Host $share -ForegroundColor Green 
    Write-Host $('-' * $share.Length) -ForegroundColor Green 
    $objShareSec = Get-WMIObject -Class Win32_LogicalShareSecuritySetting -Filter "name='$Share'"  -ComputerName $computer
    try { 
        $SD = $objShareSec.GetSecurityDescriptor().Descriptor   
        foreach($ace in $SD.DACL){  
            $UserName = $ace.Trustee.Name     
            If ($ace.Trustee.Domain -ne $Null) {$UserName = "$($ace.Trustee.Domain)\$UserName"}   
            If ($ace.Trustee.Name -eq $Null) {$UserName = $ace.Trustee.SIDString }     
            [Array]$ACL += New-Object Security.AccessControl.FileSystemAccessRule($UserName, $ace.AccessMask, $ace.AceType) 
            } #end foreach ACE           
        } # end try 
    catch 
        { Write-Host "Unable to obtain permissions for $share" } 
    $ACL 
    Write-Host $('=' * 50) 
    } # end foreach $share

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LVL 12

Accepted Solution

by:
Dustin Saunders earned 250 total points
ID: 41742460
I recently answered a similar question, which has the code you are looking for.

See below code:
$OutFile = "C:\test\output.csv"
$LookFolder = "C:\test"

function getACL($Folders, $type)
{
    foreach ($Folder in $Folders){
	$ACLs = get-acl $Folder.Path | ForEach-Object { $_.Access  }
	Foreach ($ACL in $ACLs){
	$OutInfo = $Folder.Path + "," + $ACL.IdentityReference  +  "," + $ACL.IsInherited # Additional options:: + "," + $ACL.InheritanceFlags +"," + $ACL.AccessControlType + "," + $ACL.PropagationFlags
	Add-Content -Value $OutInfo -Path $OutFile
	}}
}

$nifolders = Get-ChildItem $LookFolder -recurse | ?{$_.PSIsContainer} | Select @{Name='Path';Expression={$_.FullName}},@{Name='InheritedCount';Expression={(Get-Acl $_.FullName | Select -ExpandProperty Access | Where { $_.IsInherited }).Count}} | Where { $_.InheritedCount -eq 0} | Select Path
$ifolders = Get-ChildItem $LookFolder -recurse | ?{$_.PSIsContainer} | Select @{Name='Path';Expression={$_.FullName}},@{Name='InheritedCount';Expression={(Get-Acl $_.FullName | Select -ExpandProperty Access | Where { $_.IsInherited }).Count}} | Where { $_.InheritedCount -gt 0} | Select Path

getACL($ifolders)
getACL($nifolders)

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Where $lookFolder is the root you want to see.  This will show who has membership to the folder and if the folder has inheritance enabled.
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