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Solved
tenRun challenge
Posted on 2016-08-08
Hi,
I am working on below challenge
http://codingbat.com/prob/p199484
Psedo code description of approach :
1. create new array of given array size
2. loop given array in for loop
3. check each element value not greater than 10
4. if yes multiply by 10
5 if no give same value from given array to new array
I wrote my code as below
I am not passing all tests
Expected Run
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 20] [20, 10, 30, 40, 20, 50] X
tenRun([10, 1, 20, 2]) → [10, 10, 20, 20] [10, 10, 20, 20] OK
tenRun([10, 1, 9, 20]) → [10, 10, 10, 20] [10, 10, 90, 20] X
tenRun([1, 2, 50, 1]) → [1, 2, 50, 50] [10, 20, 50, 10] X
tenRun([1, 20, 50, 1]) → [1, 20, 50, 50] [10, 20, 50, 10] X
tenRun([10, 10]) → [10, 10] [10, 10] OK
tenRun([10, 2]) → [10, 10] [10, 20] X
tenRun([0, 2]) → [0, 0] [0, 20] X
tenRun([1, 2]) → [1, 2] [10, 20] X
tenRun([1]) → [1] [10] X
tenRun([]) → [] [] OK
other tests
X
How to improve my design, approach, code? please advise
I am working on below challenge
http://codingbat.com/prob/p199484
Psedo code description of approach :
1. create new array of given array size
2. loop given array in for loop
3. check each element value not greater than 10
4. if yes multiply by 10
5 if no give same value from given array to new array
I wrote my code as below
public int[] tenRun(int[] nums) {
int len =nums.length;
int[] arr=new int[len];
for(int i=0;i<len;i++){
if(nums[i]<10){
arr[i]=nums[i]*10;
}
else{
arr[i]=nums[i];
}
}
return arr;
}
I am not passing all tests
Expected Run
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 20] [20, 10, 30, 40, 20, 50] X
tenRun([10, 1, 20, 2]) → [10, 10, 20, 20] [10, 10, 20, 20] OK
tenRun([10, 1, 9, 20]) → [10, 10, 10, 20] [10, 10, 90, 20] X
tenRun([1, 2, 50, 1]) → [1, 2, 50, 50] [10, 20, 50, 10] X
tenRun([1, 20, 50, 1]) → [1, 20, 50, 50] [10, 20, 50, 10] X
tenRun([10, 10]) → [10, 10] [10, 10] OK
tenRun([10, 2]) → [10, 10] [10, 20] X
tenRun([0, 2]) → [0, 0] [0, 20] X
tenRun([1, 2]) → [1, 2] [10, 20] X
tenRun([1]) → [1] [10] X
tenRun([]) → [] [] OK
other tests
X
How to improve my design, approach, code? please advise
[X]
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28 Comments
Active today
CREATE, GREATER THAN, and MULTIPLY are not mentioned in the Challenge.
Work on the pseudo code, not the code.
How important is the pseudo code?
Do you realize you are actually failing all of the tests?
The only cases that pass are those where the input string is already in final form.
You can not improve your English comprehension by studying Java.
You might be able to improve your Java skills by slowing down and working on one question at a time.
But I've said that several times already and you don't seem to agree.
Work on the pseudo code, not the code.
How important is the pseudo code?
Do you realize you are actually failing all of the tests?
The only cases that pass are those where the input string is already in final form.
You can not improve your English comprehension by studying Java.
You might be able to improve your Java skills by slowing down and working on one question at a time.
But I've said that several times already and you don't seem to agree.
Active 2 days ago
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 20]i thought above should be as below according to challenge description?
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 10]
please advise
Active today
Are you familiar with the remainder operator? It is also called modulo or modulus.
You can use it in this challenge to determine whether a number is a multiple of ten .
https://docs.oracle.com/javase/tutorial/java/nutsandbolts/op1.html
http://www.javaranch.com/drive/modulo.html
https://www.google.com/?gws_rd=ssl#q=modulus+operator+java
You can use it in this challenge to determine whether a number is a multiple of ten .
https://docs.oracle.com/javase/tutorial/java/nutsandbolts/op1.html
http://www.javaranch.com/drive/modulo.html
https://www.google.com/?gws_rd=ssl#q=modulus+operator+java
Active today
>> I thought above should be as below according to challenge description?
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 10]
Why do you think that? What does the challenge say?
What do you think the results of the following should be:
tenRun([2, 20, 3, 4, 10, 5]) → ???
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 10]
Why do you think that? What does the challenge say?
What do you think the results of the following should be:
tenRun([2, 20, 3, 4, 10, 5]) → ???
Active 2 days ago
For each multiple of 10 in the given array, change all the values following it to be that multiple of 10, until encountering another multiple of 10. So {2, 10, 3, 4, 20, 5} yields {2, 10, 10, 10, 20, 20}.//however 3,4 became 10.10 i thought 5 should become 10tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 20]
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 20]
tenRun([10, 1, 20, 2]) → [10, 10, 20, 20]
tenRun([10, 1, 9, 20]) → [10, 10, 10, 20]
i thought above should be as below according to challenge description?
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 10]
What do you think the results of the following should be:
tenRun([2, 20, 3, 4, 10, 5]) → ???tenRun([2, 20, 10, 10, 10, 10])
Active today
>> However 3,4 became 10.10 i thought 5 should become 10
What multiple of 10 does the 5 follow???
What do you think the results of the following should be:
tenRun([2, 20, 3, 4, 10, 5]) → ???tenRun([2, 20, 10, 10, 10, 10])
No, that is not correct
For each multiple of 10 in the given array, change all the values following it to be that multiple of 10
And you don't change any values before the first multiple of 10.
What multiple of 10 does the 5 follow???
What do you think the results of the following should be:
tenRun([2, 20, 3, 4, 10, 5]) → ???tenRun([2, 20, 10, 10, 10, 10])
No, that is not correct
For each multiple of 10 in the given array, change all the values following it to be that multiple of 10
Doing it by hand:
tenRun([2, 20, 3, 4, 10, 5]
2 - no change
20 - multiple of 10 - no change
3 - change it 20 since it follows that multiple of 10
4 - change it 20 since it follows that multiple of 10
10 - multiple of 10 - no change
5 - change it 10 since it follows that multiple of 10
And you don't change any values before the first multiple of 10.
Active today
What do you think the results of the following should be:
tenRun([2, 10, 3, 20, 5, 1001, 10, 2001]) → ???
tenRun([2, 10, 3, 20, 5, 1001, 10, 2001]) → ???
Active 2 days ago
>> However 3,4 became 10.10 i thought 5 should become 10
What multiple of 10 does the 5 follow???//[b]not sure what it means..10*0 is 0 10*1 is 10 so 5 falls in between 0 and 5..when you say What multiple of 10 does the 5 follow i am not following it?[/b]
What do you think the results of the following should be:
tenRun([2, 20, 3, 4, 10, 5]) → ???tenRun([2, 20, 10, 10, 10, 10])
No, that is not correct
For each multiple of 10 in the given array, change all the values following it to be that multiple of 10
Doing it by hand:
tenRun([2, 20, 3, 4, 10, 5]
2 - no change
20 - multiple of 10 - no change
3 - change it 20 since it follows that multiple of 10
4 - change it 20 since it follows that multiple of 10
10 - multiple of 10 - no change
5 - change it 10 since it follows that multiple of 10//[b][i]but challenge expecting to change it to 20 not 10[/i][/b]
Active today
This is the case we are talking about now. It is one of the original test cases that you did not understand.
tenRun([2, 10, 3, 4, 20, 5]
>> However 3,4 became 10.10 i thought 5 should become 10
What multiple of 10 does the 5 follow???
>> not sure what it means..10*0 is 0 10*1 is 10 so 5 falls in between 0 and 5..when you say
What multiple of 10 does the 5 follow i am not following it?[/b]
falls between has nothing to do with following
multiple of does not mean multiply by
What multiple of 10 does the 5 follow in the array?
is the same as
What multiple of 10 comes before 5 in the array?
The answer in this case is 20. -- So change the 5 to 20.
tenRun([2, 10, 3, 4, 20, 5]
>> However 3,4 became 10.10 i thought 5 should become 10
What multiple of 10 does the 5 follow???
>> not sure what it means..10*0 is 0 10*1 is 10 so 5 falls in between 0 and 5..when you say
What multiple of 10 does the 5 follow i am not following it?[/b]
falls between has nothing to do with following
multiple of does not mean multiply by
What multiple of 10 does the 5 follow in the array?
is the same as
What multiple of 10 comes before 5 in the array?
The answer in this case is 20. -- So change the 5 to 20.
Active 2 days ago
still thinking above
What multiple of 10 does the 5 follow in the array?
is the same as
What multiple of 10 comes before 5 in the array?
The answer in this case is 20. -- So change the 5 to 20.
Active today
This is the text of the Challenge, in case you have forgotten:
For each multiple of 10 (like 0, 10, 20, 30, ...) in the given array
change all the values following it (in the array) to be that multiple of 10
until encountering another multiple of 10.
For each multiple of 10 (like 0, 10, 20, 30, ...) in the given array
change all the values following it (in the array) to be that multiple of 10
until encountering another multiple of 10.
Active 2 days ago
tenRun([2, 10, 3, 20, 5, 1001, 10, 2001]) → ??? ([2, 10, 10, 20, 20, 20, 10, 10]) → is this answer correct?
Active 2 days ago
public int[] tenRun(int[] nums) {
int len =nums.length;
int[] arr=new int[len];
for(int i=0;i<len;i++){
if((nums[i]/10)==0){
arr[i]=10*(nums[i]%10);
}
else{
arr[i]=nums[i];
}
}
return arr;
}
i think now i understood challene trying to fix it and failing due to not able to start from first occurence of 10 multiple but starting from index 0
Expected Run
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 20] [20, 10, 30, 40, 20, 50] X
tenRun([10, 1, 20, 2]) → [10, 10, 20, 20] [10, 10, 20, 20] OK
tenRun([10, 1, 9, 20]) → [10, 10, 10, 20] [10, 10, 90, 20] X
tenRun([1, 2, 50, 1]) → [1, 2, 50, 50] [10, 20, 50, 10] X
tenRun([1, 20, 50, 1]) → [1, 20, 50, 50] [10, 20, 50, 10] X
tenRun([10, 10]) → [10, 10] [10, 10] OK
tenRun([10, 2]) → [10, 10] [10, 20] X
tenRun([0, 2]) → [0, 0] [0, 20] X
tenRun([1, 2]) → [1, 2] [10, 20] X
tenRun([1]) → [1] [10] X
tenRun([]) → [] [] OK
other tests
X
Your progress graph for this problem
Active 2 days ago
how to start for loop from first occurrence of 10 multiple not from i=0 which resolve the issues here
Active today
You are still multiplying by 10.
That is wrong.
You have to start at 0 to look for the first multiple of 10.
What is your pseudo code?
That is wrong.
You have to start at 0 to look for the first multiple of 10.
What is your pseudo code?
Active today
tenRun([2, 10, 3, 20, 5, 1001, 10, 2001]) → ??? ([2, 10, 10, 20, 20, 20, 10, 10]) → is this answer correct?
Yes, but your code is not even close.
Where is your pseudo code?
Yes, but your code is not even close.
Where is your pseudo code?
Active today
You should use the remainder operator to make your search. See my first comment above here.
Active 2 days ago
how to use moduls operator for this challenge?
Psedo code description of approach :
1. create new array of given array size
2. loop given array in for loop
3. check each element value modulus is 0(ie reminder)
4. if yes multiply subsequent elements by same previous element value?
5 if no give same value from given array to new array
Psedo code description of approach :
1. create new array of given array size
2. loop given array in for loop
3. check each element value modulus is 0(ie reminder)
4. if yes multiply subsequent elements by same previous element value?
5 if no give same value from given array to new array
Active today
how to use moduls operator for this challenge?You can search for the condition
nums[i]%10) == 0
4. if yes multiply subsequent elements by same previous element value?No. As d-glitch has posted
... MULTIPLY are not mentioned in the Challenge.Multiply is an arithmetic operation. If we multiply 3 by 4 the result is 12. The numbers that are multiples of ten are 10, 20 ,30, 40, and so on.
Active 2 days ago
public int[] tenRun(int[] nums) {
int totalLen =nums.length;
//int[] arr=new int[len];
int firstVal=0;
for(int i=0;i<totalLen;i++){
if((nums[i]%10)==0){
firstVal=i;
break;
}
}
for(int k=firstVal;k<totalLen;k++){
if((nums[k]%10)==0){
secondVal=k;
break;
}
}
return nums;
}
i tried above approach. I have to print all values between firstval and secondval which i am not able to figure out how to proceed further esp if there is thirdval and fourthvale etc
Active today
Go through the array one element at a time.
Do nothing until you find a multiple of 10. You need a flag.
Once you find one you will use to replace later elements. Remember it.
The rest of the array elements are either replaced or used to update replacer.
Do nothing until you find a multiple of 10. You need a flag.
Once you find one you will use to replace later elements. Remember it.
The rest of the array elements are either replaced or used to update replacer.
Active 2 days ago
public int[] tenRun(int[] nums) {
int totalLen =nums.length;
//int[] arr=new int[len];
int val=0;
boolean tenFlag=false;
for(int i=0;i<totalLen;i++){
if((nums[i]%10)==0){
val=nums[i];
tenFlag=true;
}
else if((nums[i]%10)!=0&&tenFlag){
nums[i]=val;
}
}
return nums;
}
now I passed all tests
Expected
Run
tenRun([2, 10, 3, 4, 20, 5]) → [2, 10, 10, 10, 20, 20] [2, 10, 10, 10, 20, 20] OK
tenRun([10, 1, 20, 2]) → [10, 10, 20, 20] [10, 10, 20, 20] OK
tenRun([10, 1, 9, 20]) → [10, 10, 10, 20] [10, 10, 10, 20] OK
tenRun([1, 2, 50, 1]) → [1, 2, 50, 50] [1, 2, 50, 50] OK
tenRun([1, 20, 50, 1]) → [1, 20, 50, 50] [1, 20, 50, 50] OK
tenRun([10, 10]) → [10, 10] [10, 10] OK
tenRun([10, 2]) → [10, 10] [10, 10] OK
tenRun([0, 2]) → [0, 0] [0, 0] OK
tenRun([1, 2]) → [1, 2] [1, 2] OK
tenRun([1]) → [1] [1] OK
tenRun([]) → [] [] OK
other tests
OK
Active today
Here is my code.
public int[] tenRun(int[] nums) {
int current = 1;
for(int i=0;i<nums.length; i++){
if((nums[i]%10) == 0){
current = nums[i];
}
else{
if(current != 1) nums[i] = current;
}
}
return nums;
}
Active today
Yes, you can combine the flag and the currVal variables for a more elegant solution.
You can come up with this sort of trick if you focus your thinking on algorithms and optimizations. You will never come up with them if you keep asking for basic help.
You are currently working on a problem that can use this exact trick. Good luck.
You can come up with this sort of trick if you focus your thinking on algorithms and optimizations. You will never come up with them if you keep asking for basic help.
You are currently working on a problem that can use this exact trick. Good luck.
Active 2 days ago
You are currently working on a problem that can use this exact trick.
how to combine this?
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