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C# Linq Remove All

Is there a shorter way to write this so no  looping is involved?
                        for (int i = 0; i < data.Count; i++)
                        {
                            myObject.RemoveAll(x => x.Name == data[i].Name &&
                                                  x.Description == data[i].Description;
                        }

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CipherIS
Asked:
CipherIS
1 Solution
 
Prakash SamariyaIT ProfessionalCommented:
Try linq code like below:
myObject.RemoveAll(
	x => data.Exists(
		y=> { 
			y.Name ==x.Name && y.Description==x.Description
		}
	)
);

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CipherISAuthor Commented:
Thanks that work with minor modification.
myObject.RemoveAll(
		x => data.Exists(
				y => y.Name == x.Name && 
				y.Description == x.Description
                  )
);

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