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SQL Server Set bit value based on sums

Posted on 2016-08-11
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Last Modified: 2016-08-12
I have a table that I want to query once each morning
I want to get a sum of the totalCOunt column
If that total is > 175,000
And then however many ID's there are (Should be 5 to 20
Get the bottom ID's that together SUM(totalCount) <= 125,000
And set outsideBit = 1
So that at the end of the query the ID's will not be in the top when sorted by ID
And the sum of thos ID's is <= 125,000

Here are the three columns
ID   totalCount    outsideBIT
1     12532                0
2     12658                0
etc...
0
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Question by:lrbrister
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4 Comments
 
LVL 11

Expert Comment

by:CraigYellick
ID: 41753063
First step is to determine if the sum of totalCount > 175,000. Below I assume that outsideBIT has been set to zero and is not relevant as this stage. If it is, you can always add a WHERE clause to the SELECT statement.

dim n as integer
dim rs as DAO.Recordset
dim db as DAO.Database
set db = CurrentDB()
set rs = db.OpenRecordset("select sum(totalCount) from T")
if not rs.eof then
  n = rs(0)
  if n > 175000 then
    'take action
  end if 
end if

Open in new window

Let me know if the above is going to work for you. If so, we can move on to setting the bit flag. If not we need to adjust things to fit your situation.

-- Craig
0
 
LVL 49

Accepted Solution

by:
PortletPaul earned 500 total points
ID: 41753145
declare @Table1 table
    ([id] int, [totalCount] int)
;
    
INSERT INTO @Table1
    ([id], [totalCount])
VALUES
    (1, 20000),
    (2, 20000),
    (3, 20000),
    (4, 20000),
    (5, 20000),
    (6, 20000),
    (7, 20000),
    (8, 20000),
    (9, 20000),
    (10, 20000)
;

select top(1)
    id
from (
      select
       id
      , sum(totalCount) over(order by id DESC) id_low
      , sum(totalCount) over(partition by (select 1)) all_count
      from @table1
      ) t
where all_count > 175000 and id_low <= 125000
order by id_low DESC
;

      select
       id
      , sum(totalCount) over(order by id DESC) id_low
      , sum(totalCount) over(partition by (select 1)) all_count
      from @table1

Open in new window

id 
-- 
5  

(1 row(s) returned)

(10 row(s) affected)

id id_low all_count 
-- ------ --------- 
10 20000  200000    
9  40000  200000    
8  60000  200000    
7  80000  200000    
6  100000 200000    
5  120000 200000    
4  140000 200000    
3  160000 200000    
2  180000 200000    
1  200000 200000    

(10 row(s) returned)

(10 row(s) affected)

Open in new window

can you illustrate what you wan with sample data and expected result?
0
 

Author Comment

by:lrbrister
ID: 41753321
Guys
I will be at my PC in a few hours to check these
0
 

Author Closing Comment

by:lrbrister
ID: 41753766
This is exactly what I needed... it returned correctly #5
0

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