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child constructor and parent constructor, overriding and overloading

Hi,

I am running my code as below
public class Child extends Parent{
    public Child(int i) {
		// TODO Auto-generated constructor stub
    	System.out.println("in Child constructor");
	}

	public static void main(String[] args) {
		Child ch = new Child(4);
        ch.print();
    }
}

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public class Parent{
    protected int number = 9;

    public Parent() {
    	System.out.println("in Parent no arg construcot");
        this.number = 11;
    }

    public Parent(int number) {
    	System.out.println("in Parent arg construcot");
        this.number = number;
    }

    protected void print() {
        System.out.print(number);
    }
}

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when i run child class as java application i got below output
in Parent no arg construcot
in Child constructor
11


My question is since i am calling arument construcor of child as below
Child ch = new Child(4);

Am i not supposed to be called parent arg constructor (rather it is calling parent no argument constructor) . please advise.

i expected instead below output


in Parent no arg construcot
in Parent arg construcot
in Child constructor
11
0
gudii9
Asked:
gudii9
3 Solutions
 
Jeffrey Dake Senior Director of TechnologyCommented:
you need to call super(i); as your first call in your child class constructor. This will tell the parent class to use the constructor with the argument.
0
 
Guy Hengel [angelIII / a3]Billing EngineerCommented:
public static void main(String[] args) {
            Child ch = new Child(4);
        ch.print();
    }

note that this will create a new child object, and not set the "current" object itself with an argument...

so, when you run the code, and Child being the "main class", it will first create that main class (with the parent no arg constructor), and then run main(), which creates a new Child object with argument...
0
 
CPColinCommented:
Jeff is right. Per this section of the language specification:

If a constructor body does not begin with an explicit constructor invocation and the constructor being declared is not part of the primordial class Object, then the constructor body implicitly begins with a superclass constructor invocation "super();", an invocation of the constructor of its direct superclass that takes no arguments.

So the constructor in your Child class, as it's currently written, is calling the no-arg Parent() constructor.

Guy,

so, when you run the code, and Child being the "main class", it will first create that main class (with the parent no arg constructor), and then run main(), which creates a new Child object with argument

Since main is static, the JVM does not need to create an instance of Child before executing it.
1
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gudii9Author Commented:
public class Parent{
    protected int number = 9;

    public Parent() {
    	System.out.println("in Parent no arg construcot");
        this.number = 11;
    }

    public Parent(int number) {
    	System.out.println("in Parent arg construcot");
        this.number = number;
    }

    protected void print() {
        System.out.print(number);
    }
}

Open in new window


public class Child extends Parent{
    public Child(int i) {
		// TODO Auto-generated constructor stub
    	super(4);
    	System.out.println("in Child constructor");
	}

	public static void main(String[] args) {
		Child ch = new Child(4);
        ch.print();
    }
}

Open in new window


above gave below output

in Parent arg construcot
in Child constructor
4


which makes sense
0
 
gudii9Author Commented:
is there is a way i can see below kind of output

in Parent no arg construcot
in Parent arg construcot
in Child constructor
4


Basically i wan to see parent no arg as well arg constructors?
public class Child extends Parent{
    public Child(int i) {
		// TODO Auto-generated constructor stub
    	super();
    	super(4);
    	System.out.println("in Child constructor");
	}

	public static void main(String[] args) {
		Child ch = new Child(4);
        ch.print();
    }
}

Open in new window

if i write as aboave getting below error at line 5
Constructor call must be the first statement in a constructor

please advise
0
 
Jeffrey Dake Senior Director of TechnologyCommented:
No only one constructor is called at the parent class level. If you really need tha kind of functionality, I would create a new function that you call within the constructor. While you can only call one super call in your child class, immediately after you could call the function you declared in the parent class.
0

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