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Hi,

I am working on below challenge

http://codingbat.com/prob/p158767

I have not understood the description properly

please advise

I am working on below challenge

http://codingbat.com/prob/p158767

I have not understood the description properly

Given a non-empty array, return true if there is a place to split the array so that the sum of the numbers on one side is equal to the sum of the numbers on the other side.

canBalance([1, 1, 1, 2, 1]) → true//i thought since 1+1 is not equal to 2+1 it should be false?

canBalance([2, 1, 1, 2, 1]) → false//i thought since 2+1 is equal to 2+1 it should be true??

canBalance([10, 10]) → true

please advise

But, they want us to split the array into two pieces

front and back

break at what index or point? just randomly we can break?

break at what index or point? just randomly we can break?

They want us to split the array into two parts that balance.

[1, 1, 1, 2, 1] can balance 1+1+1 == 2 +1

[2, 2,1,5] can balance 2+2+1 == 5

We are search for the condition that front == back

So, we have to search for the balance point.

for( each split point in array){

for( each element from first to split ){ add them up}

for( each element from split to last){add them up}

if front equals back return true

}

For it to be possible the sum of the full array must be ?????

If it is possible then there is no need to search

Sum from the front of the array until FrontSum = ??????

mlmcc

1. loop through array from start

2. find the sum of left hand side

3. loop from backwards similar way

4. find the sum from right hand side

5. if both above sums equal return true

6. else return false.

below failing few tests . please advise

```
public boolean canBalance(int[] nums) {
for (int i = 0; i < nums.length; i++) {
int leftTotal=0;
leftTotal=leftTotal+nums[i];
for (int j = nums.length-1; j >i; j--) {
int rightTotal=0;
rightTotal=rightTotal+nums[i];
if(rightTotal==leftTotal){
return true;
}
}
}
return false;
}
```

Expected Run

canBalance([1, 1, 1, 2, 1]) → true true OK

canBalance([2, 1, 1, 2, 1]) → false true X

canBalance([10, 10]) → true true OK

canBalance([10, 0, 1, -1, 10]) → true true OK

canBalance([1, 1, 1, 1, 4]) → true true OK

canBalance([2, 1, 1, 1, 4]) → false true X

canBalance([2, 3, 4, 1, 2]) → false true X

canBalance([1, 2, 3, 1, 0, 2, 3]) → true true OK

canBalance([1, 2, 3, 1, 0, 1, 3]) → false true X

canBalance([1]) → false false OK

canBalance([1, 1, 1, 2, 1]) → true true OK

other tests

X

```
public class CanBalance {
public static void main(String[] args) {
// TODO Auto-generated method stub
int[] ar={1,1,1,2,1};
System.out.println("canBalance value is--->"+canBalance(ar));
}
public static boolean canBalance(int[] nums) {
for (int i = 0; i < nums.length; i++) {
int leftTotal=0;
leftTotal=leftTotal+nums[i];
for (int j = nums.length-1; j >i; j--) {
int rightTotal=0;
rightTotal=rightTotal+nums[i];
if(leftTotal==rightTotal){
return true;
}
}
}
return false;
}
}
```

canBalance value is--->true

```
public class CanBalance {
public static void main(String[] args) {
// TODO Auto-generated method stub
int[] ar={1,1,1,2,1};
System.out.println("canBalance value is--->"+canBalance(ar));
}
public static boolean canBalance(int[] nums) {
for (int i = 0; i < nums.length; i++) {
int leftTotal=0;
leftTotal=leftTotal+nums[i];
System.out.println("i is " + i + " leftTotal is " + leftTotal);
for (int j = nums.length-1; j >i; j--) {
int rightTotal=0;
rightTotal=rightTotal+nums[i];
System.out.println("j is " + j + " rightTotal is " + leftTotal);
if(leftTotal==rightTotal){
return true;
}
}
}
return false;
}
}
```

The output isi is 0 leftTotal is 1

j is 4 rightTotal is 1

canBalance value is--->true

Now we see what the machine is doing. It is just comparing the first element with the first element. Which is true for this particular input.

Now let's change input to {1, 2, 3, 1, 0, 1, 3}

The output now is

i is 0 leftTotal is 1

j is 6 rightTotal is 1

canBalance value is--->true

With the debug statements I have added, the code should print the totals in every iteration. Your code just stops after a single iteration. Another thing we can see from the second test, this statement

```
rightTotal=rightTotal+nums[i];
```

is wrong. rightTotal should have equal to 3(at that point). You have i where you should have j.
You are resetting the total to 0 each time through the loop.

The loops should calculate the total from that direction so the reset should be ????

mlmcc

```
public boolean canBalance(int[] nums) {
int leftTotal=0;
int rightTotal=0;
for (int i = 0; i < nums.length; i++) {
leftTotal=leftTotal+nums[i];
// System.out.println("i is " + i + " leftTotal is " + leftTotal);
for (int j = nums.length-1; j >i; j--) {
rightTotal=rightTotal+nums[j];
// System.out.println("j is " + j + " rightTotal is " + rightTotal);
if(leftTotal==rightTotal){
return true;
}
}
}
return false;
}
```

passed couple of more tests

Expected Run

canBalance([1, 1, 1, 2, 1]) → true true OK

canBalance([2, 1, 1, 2, 1]) → false false OK

canBalance([10, 10]) → true true OK

canBalance([10, 0, 1, -1, 10]) → true true OK

canBalance([1, 1, 1, 1, 4]) → true false X

canBalance([2, 1, 1, 1, 4]) → false false OK

canBalance([2, 3, 4, 1, 2]) → false true X

canBalance([1, 2, 3, 1, 0, 2, 3]) → true false X

canBalance([1, 2, 3, 1, 0, 1, 3]) → false false OK

canBalance([1]) → false false OK

canBalance([1, 1, 1, 2, 1]) → true true OK

other tests

OK

```
public class CanBalance {
public static void main(String[] args) {
// TODO Auto-generated method stub
//int[] ar={1,1,1,2,1};
//System.out.println("canBalance value is--->"+canBalance(ar));
//2, 1, 1, 2, 1
int[] ar1={1, 2, 3, 1, 0, 1, 3};
System.out.println("canBalance value is--->"+canBalance(ar1));
}
public static boolean canBalance(int[] nums) {
int leftTotal=0;
int rightTotal=0;
for (int i = 0; i < nums.length; i++) {
leftTotal=leftTotal+nums[i];
System.out.println("i is " + i + " leftTotal is " + leftTotal);
for (int j = nums.length-1; j >i; j--) {
rightTotal=rightTotal+nums[j];
System.out.println("j is " + j + " rightTotal is " + rightTotal);
if(leftTotal==rightTotal){
return true;
}
}
}
return false;
}
}
```

i is 0 leftTotal is 1

j is 6 rightTotal is 3

j is 5 rightTotal is 4

j is 4 rightTotal is 4

j is 3 rightTotal is 5

j is 2 rightTotal is 8

j is 1 rightTotal is 10

i is 1 leftTotal is 3

j is 6 rightTotal is 13

j is 5 rightTotal is 14

j is 4 rightTotal is 14

j is 3 rightTotal is 15

j is 2 rightTotal is 18

i is 2 leftTotal is 6

j is 6 rightTotal is 21

j is 5 rightTotal is 22

j is 4 rightTotal is 22

j is 3 rightTotal is 23

i is 3 leftTotal is 7

j is 6 rightTotal is 26

j is 5 rightTotal is 27

j is 4 rightTotal is 27

i is 4 leftTotal is 7

j is 6 rightTotal is 30

j is 5 rightTotal is 31

i is 5 leftTotal is 8

j is 6 rightTotal is 34

i is 6 leftTotal is 11

canBalance value is--->false

Trying to fox them too

i is 0 leftTotal is 1

j is 4 rightTotal is 4

j is 3 rightTotal is 5

j is 2 rightTotal is 6

j is 1 rightTotal is 7

j is 4 rightTotal is 11

issue now is when i=i then jstarts from 4 again and the total needs to reset to 0 and start total with 5 then 5 for j=3 etc...which is not happening now?

My solution has nested for loops . Something like

for( whole array){

for( front){ add them}

for( back){add them}

if front equals back return true

}

i see it. i am still thinking iif there is a way to fix with 2 loops if yes 3 loops unnecessary right?

int leftTotal=0;

int rightTotal=0;

do i need to define above two on top of outer for loop ( for (int i = 0; i < nums.length; i++) { )or one on top of outer for loop and another one(int rightTotal=0;) on top of inner for loop( for (int j = nums.length-1; j >i; j--) {)

```
public boolean canBalance(int[] nums) {
int leftTotal=0;
for (int i = 0; i < nums.length; i++) {
leftTotal=leftTotal+nums[i];
// System.out.println("i is " + i + " leftTotal is " + leftTotal);
int rightTotal=0;
for (int j = nums.length-1; j >i; j--) {
rightTotal=rightTotal+nums[j];
//System.out.println("j is " + j + " rightTotal is " + rightTotal);
}
if(leftTotal==rightTotal){
return true;
}
}
return false;
}
```

above passed all tests. I have to take out the if loop from inner for loop and also place rightTotal above inner for loop as below

int rightTotal=0;

for (int j = nums.length-1; j >i; j--) {

do i need to define ....I don't know. I can't really understand your code(thinking). My thoughts :

in each iteration of outer for loop

add left

add right

if equal then break out

else reset

```
public class CanBalance {
public static void main(String[] args) {
int[] ar1={2, 1, 1, 2, 1};
System.out.println("canBalance value is--->"+canBalance(ar1));
}
public static boolean canBalance(int[] nums) {
int leftTotal=0;
for (int i = 0; i < nums.length; i++) {
leftTotal=leftTotal+nums[i];
System.out.println("i is " + i + " leftTotal is " + leftTotal);
int rightTotal=0;
for (int j = nums.length-1; j >i; j--) {
rightTotal=rightTotal+nums[j];
System.out.println("j is " + j + " rightTotal is " + rightTotal);
}
if(leftTotal==rightTotal){
return true;
}
}
return false;
}
}
```

i is 0 leftTotal is 2any improvements, modifications, refinement to above code? how does your code looks like?

j is 4 rightTotal is 1

j is 3 rightTotal is 3

j is 2 rightTotal is 4

j is 1 rightTotal is 5

i is 1 leftTotal is 3

j is 4 rightTotal is 1

j is 3 rightTotal is 3

j is 2 rightTotal is 4

i is 2 leftTotal is 4

j is 4 rightTotal is 1

j is 3 rightTotal is 3

i is 3 leftTotal is 6

j is 4 rightTotal is 1

i is 4 leftTotal is 7

canBalance value is--->false

add left

start iteration of inner for loop

add right

if equal then return true

else return false

YOu need to test for equality after each time you add the right value.

is that is reason why

I have to take out the if loop from inner for loop and also place rightTotal above inner for loop(not above outer for loop) as below??

int rightTotal=0; for (int j = nums.length-1; j >i; j--) {

```
public class CanBalance {
public static void main(String[] args) {
int[] ar={4, 2, 3, 3};
System.out.println("canBalance value is--->"+canBalance(ar));
}
public static boolean canBalance(int[] nums) {
boolean result = false;
int front = 0;
int back = 0;
for(int i = 0; i < nums.length; i++){
for(int f = 0; f < i + 1 ; f++){
front += nums[f];
System.out.println("f is " + f + " front is " + front);
}
for(int b = i + 1; b < nums.length ; b++){
back += nums[b];
System.out.println("b is " + b + " back is " + back);
}
if(front == back){
result = true;
break;
}
else{
front = 0;
back = 0;
}
}
return result;
}
}
```

Output was f is 0 front is 4

b is 1 back is 2

b is 2 back is 5

b is 3 back is 8

f is 0 front is 4

f is 1 front is 6

b is 2 back is 3

b is 3 back is 6

canBalance value is--->true

I stubbornly held to my first thoughts. I wastefully added the front(left) over and over. Your way is better.

add left

start iteration of inner for loop

add right

if equal then return true

Loop inner

Loop outer

return false

mlmcc

add left

start

add right

if equal then return true

Loop outer

return false

how looping is different from iteration? i am thinking both same?

Only difference with your code is where you test for equality

mlmcc

Only difference with your code is where you test for equality

how your code looks like? did you use if loop inside inner for loo?

```
public boolean canBalance(int[] nums) {
int leftTotal=0;
int rightTotal=0;
for (int i = 0; i < nums.length; i++) {
leftTotal=leftTotal+nums[i];
// System.out.println("i is " + i + " leftTotal is " + leftTotal);
// int rightTotal=0;
for (int j = nums.length-1; j >i; j--) {
rightTotal=rightTotal+nums[j];
//System.out.println("j is " + j + " rightTotal is " + rightTotal);
}
if(leftTotal==rightTotal){
return true;
}
}
return false;
}
```

Expected Run

canBalance([1, 1, 1, 2, 1]) → true false X

canBalance([2, 1, 1, 2, 1]) → false false OK

canBalance([10, 10]) → true true OK

canBalance([10, 0, 1, -1, 10]) → true true OK

canBalance([1, 1, 1, 1, 4]) → true false X

canBalance([2, 1, 1, 1, 4]) → false false OK

canBalance([2, 3, 4, 1, 2]) → false false OK

canBalance([1, 2, 3, 1, 0, 2, 3]) → true false X

canBalance([1, 2, 3, 1, 0, 1, 3]) → false false OK

canBalance([1]) → false false OK

canBalance([1, 1, 1, 2, 1]) → true false X

other tests

OK

why above code fails some tests if i move rightSum initialization line to the top of outer for loop rather than inner for loop??

```
int rightTotal=0;
for (int i = 0; i < nums.length; i++) {
```

why above code fails some tests if i move rightSum initialization line to the top of outer for loop rather than inner for loop??because you are not resetting the total value.

i is 0 leftTotal is 2

j is 4 rightTotal is 1

j is 3 rightTotal is 3

j is 2 rightTotal is 4

j is 1 rightTotal is 5

i is 1 leftTotal is 3

j is 4 rightTotal is 1

j is 3 rightTotal is 3

j is 2 rightTotal is 4

i is 2 leftTotal is 4

j is 4 rightTotal is 1

j is 3 rightTotal is 3

i is 3 leftTotal is 6

j is 4 rightTotal is 1

i is 4 leftTotal is 7

canBalance value is--->false

I see difference. As given below right Sum never resetted back to 0 if it is above outer loop. where as resetted perfectly if above inner for loop producing correct output as above

i is 0 leftTotal is 2

j is 4 rightTotal is 1

j is 3 rightTotal is 3

j is 2 rightTotal is 4

j is 1 rightTotal is 5

i is 1 leftTotal is 3

j is 4 rightTotal is 6

j is 3 rightTotal is 8

j is 2 rightTotal is 9

i is 2 leftTotal is 4

j is 4 rightTotal is 10

j is 3 rightTotal is 12

i is 3 leftTotal is 6

j is 4 rightTotal is 13

i is 4 leftTotal is 7

canBalance value is--->false

because you are not resetting the total value.

now it is clear.

If given array is {1,1,1,1,4}

i legtTotal j rightTotal(// i wonder how to draw a table in EE?)

0 1 4 4

3 5

2 6

1 7

1 2 4 4//here we need 4 value (which comes if i initialize rightTotal on top of inner for loop as it resetted when j inner loop start over triggered by increment of i from 0 to 1 etc...not 11 which comes if initializeat top of outer for loop as it keep on adding total till outer i loop completes.

Also if (leftTotal == rightTotal) check still inside outer for loop even though it is outside inner for loop which is whagt we wanted(to check each value of i we are finding all rightTotal values comparing with leftTotals.

i am closing this now

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front and middle and back

But, they want us to split the array into two pieces

front and back

[1, 1, 1, 2, 1] can balance 1+1+1 == 2 +1

[2, 1, 1, 2, 1] can't balance

[2, 2,1,5] can balance 2+2+1 == 5

My solution has nested for loops . Something like

for( whole array){

for( front){ add them}

for( back){add them}

if front equals back return true

}