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open excel file from code

Posted on 2016-08-17
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Last Modified: 2016-08-17
excel 2010 vba

I have a command button on a form to open excel files.
I need it revamped to: Only open a specific excel file name(provided in code) from a specific folder on a server

MyFile.xls
or
MyFile.xlsx



10.xx.xxx.xx\c:\mydata\folderTemp


Sub XET_OpenAllXfilesInFolder()
    fldr = GetFolder(ActiveWorkbook.Path)
    xfile = Dir(fldr & "\*.xlsx")
    Do While xfile <> ""
        Workbooks.Open Filename:=fldr & "\" & xfile
    Loop
End Sub
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Question by:fordraiders
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6 Comments
 
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Accepted Solution

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Martin Andrews earned 500 total points
ID: 41760001
You simply need to use the open function with the hardcoded values for fpath and fname

Dim owb As Workbook
owb = Workbooks.Open(fpath & "\" & fname)

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Author Comment

by:fordraiders
ID: 41760018
getting object variable with block varaiable not set.
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Author Comment

by:fordraiders
ID: 41760035
Dim sPath As String
Dim sFile As String
Dim sDir As String
Dim oLB As Workbook
Dim i1 As Long
Dim iMax As Long
 
sPath = "C:\Program Files\prise\iuom\"
sDir = FileSystem.Dir(sPath & "Version_iUom_Enterprise.xls", vbNormal)
 
    Set oLB = Workbooks.Open(sPath & sDir)


This working with no errors but i do not see the workbook.
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Author Comment

by:fordraiders
ID: 41760044
Workbooks.Application.Visible = true
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Author Closing Comment

by:fordraiders
ID: 41760045
Thanks
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Expert Comment

by:Martin Andrews
ID: 41760050
If your original code was working ng, you can simply use that, the point is that you simply set it manually in your code rather than letting the user select it:

Dim own as Workbook
Workbooks.Open Filename:=fpath & "\" & fname
Set owb = ActiveWorkbook

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