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# Powershell script to remove any line with extra double quote "

Posted on 2016-08-19
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I have a text file that need to import into database, sometimes the import failed due to extra double quote found in the line, so before performing the import how do I use PS script to scan every line and remove unwanted extra doule quote.

as we seen below, between delimiter "$" , we have extra double quote in "Maxis Segar ", this is only example but we have many like this in the text lines. "$"Limited  Company "Maxis Segar ""$" 0 Question by:motioneye 13 Comments LVL 17 Expert Comment ID: 41762150 There's probably a bunch of ways to do this. But here's a quickie. foreach ($line in $file) {$line -replace '("\$"[\w\s]*)(")?([\w\s]+)?(")?("\$")','$1$3$5' }  It is matching your specific example patterns though. EG: "$"Limited  Company "Maxis Segar ""$" "$"Limited  Company Maxis Segar "$" "$"Blah Blah "$" "$"sdfsdfsdf "Blah Blah" "$" 0 LVL 12 Expert Comment ID: 41762168$test = Get-Content C:\IT\querry.txt

$newtest =$test -replace '""' , '"'

$newtest > c:\it\newquerry.txt 0 LVL 69 Expert Comment ID: 41762297 Benjamin, it is not about replacing two successive double quotes only - each double quote inside of the delimiters should get removed. Another way to do it is to remove the delimiters, remove double quotes, then add back delimiters: Get-Content file.txt -replace '"\$"', '' -replace '"', '' -replace '(.+)', '"$"$1"$"' | Out-File file2.txt  There are no real pros or cons compared to -replace '("\$"[\w\s]*)(")?([\w\s]+)?(")?("\$")','$1$3$5' or similar regular expressions.
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Author Comment

ID: 41765051
Hi,

I'm trying with one of the example script here but getting error as below.

Windows PowerShell

PS C:\Users\BDXTY> Get-Content D:\Programs\actual\Folder3\Output\SolidFile.csv -replace '"\$"', '' -replace '"', '' -replace '(.+)', '"$"$1"$"' | Out-File D:\Programs\actual\Folder3\Output\SolidFile.csv
Get-Content : A parameter cannot be found that matches parameter name 'replace'.
At line:1 char:47
+ Get-Content D:\Programs\actual\Folder3\Output\SolidFile.csv -replace '"\$"', '' -replace '"', ... + ~~~~~~~~ + CategoryInfo : InvalidArgument: (:) [Get-Content], ParameterBindingException + FullyQualifiedErrorId : NamedParameterNotFound,Microsoft.PowerShell.Commands.GetContentCommand PS C:\Users\BDXTY> 0 LVL 69 Expert Comment ID: 41765126 Sorry, forgot to copy the parens over to EE: (Get-Content D:\Programs\actual\Folder3\Output\SolidFile.csv) -replace '"\$"', '' -replace '"', '' -replace '(.+)', '"$"$1"$"' | Out-File D:\Programs\actual\Folder3\Output\SolidFile.csv  Also, be careful, you are overwriting the original file. Dangerous if in a pipe, which reads the file content while it processes (and replaces) it - leading to an empty output file ... The parens take care of that, as file content is first read in completely before getting processed. 0 Author Comment ID: 41766422 Hi Qlemo. The script works but somehow it removed all double quote for each column delimeter, from the example below. "$"Limited  Company "Maxis Segar ""$" It should be like this "$"Limited  Company Maxis Segar "$" 0 LVL 69 Expert Comment ID: 41766696 With above input it generates the above output. If it does not for you, can you please post an input and output file, as you get it? 0 Author Comment ID: 41768223 Hi Qlemo You can try with this input file attached here, What I would like this scripts does for me is to preserve all "$"  but only remove those extra double quote within a delimiter.
input.csv
0

LVL 69

Assisted Solution

Qlemo earned 500 total points
ID: 41768393
This is the first line (the header) of the input file:
"buildingName"$"c"$"cn"$"co"$"dn"$"employeeNumber"$"employeeType"$"givenName"$"mxsBusinessRegion"$"mxsBusinessRegionAcronym"$"mxsCrossCompanyManager"$"mxsExpectedEndDate"$"mxsGlobalID"$"mxsJobFamily"$"mxsLocationCode"$"mxsOrganizationChart"$"mxsOrganizationChartAcronym"$"mxsStartDate"$"mxsStatus"$"mxsTerminationDate"$"l"$"mail"$"mail"$"mail"$"mail"$"mail"$"mail"$"mail"$"mail"$"mail"$"mail"$"manager"$"managerEmployeeNumber"$"mobile"$"ntUserDomainId"$"o"$"sn"$"telephoneNumber"$"uid"$ and that is something completely different (and unexpected): The delimiter is a dollar sign only, the double quotes are enclosing each field, but embedded quotes are not doubled. Even worse, the header does not contain unique column names. Whoever creates this file: shame on you! This should work: (get-content .\input.csv) -replace '"\$"', '|' -replace '"', '' -replace '\|', '"$"' -replace '(.+)\$', '"$1"$' | Out-File .\input.csv

0

Author Comment

ID: 41769851
Hi,
One more issues that  puzzled me now, I tried with creating many entries in the text file by simply duplicating the 1st line in text file to multiple entry to be exact 1000 duplicate line. I ran the command again, at this time the size of the text file was double, as shown in the screenshot, any reasons why this happened?
Capture.PNG
0

Author Comment

ID: 41769924
Hi Qlemo,
I managed to resolved this, by adding -encoding ASCII, than the file has the same size as the original file.
Btw, don't you mind to explain how this works at every -replace ? what actually it does here ...

-replace '"\$"', '|' -replace '"', '' -replace '\|', '"$"' -replace '(.+)\$', '"$1"$' 0 LVL 69 Accepted Solution Qlemo earned 500 total points ID: 41770003 Best if you try yourself on a small file, by removing all replaces but the first, then add the next etc., and view on screen. 1. -replace '"\$"', '|' : Replace all "$" by |. I assume there will never be a pipe symbol in the data, so we can use that as field delimiter. The resulting line will have something like "data|data "quoted inline data"|data"$.
Note the trailing dollar sign - it should not be there for correct CSV, and we will need to take care of it later.
We need to escape the dollar sign with a backslash as dollar has a special meaning in regular expressions.
2. -replace '"', '': Remove the remaining double quotes.
Result: data|data quoted inline data|data$3. -replace '\|', '"$"': Replace the pipe back with the original delimiter "$". Again, pipe has a special regexp meaning and needs to be escaped. Result: data"$"data quoted inline data"$"data$
4. -replace '(.+)\$', '"$1"$': This just adds the missing double quote in front of the trailing dollar sign. Result: data"$"data quoted inline data"$"data"$
0

Author Closing Comment

ID: 41775772
Thanks Qlemo, you always be  nice and helping us here :)
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