Want to protect your cyber security and still get fast solutions? Ask a secure question today.Go Premium

x
?
Solved

SQL Date Range Syntax Assistance

Posted on 2016-08-19
3
Medium Priority
?
65 Views
Last Modified: 2016-08-22
I have the need to calculate a 'season to date' date range and add it to my query below. Our season runs as follows January thru Jun and July thru December so if the current month is August my output should be 07/01/2016 AS STDStartDate and 12/31/2016 AS STDEndDate

SELECT  DATEADD(wk, 0,
                DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()),
                        DATEDIFF(dd, 0, GETDATE()))) AS WkStartDate ,
        DATEADD(wk, 1,
                DATEADD(DAY, 0 - DATEPART(WEEKDAY, GETDATE()),
                        DATEDIFF(dd, 0, GETDATE()))) AS WkEndDate ,
        DATEADD(mm, DATEDIFF(mm, 0, GETDATE()), 0) AS MthStartDate ,
        DATEADD(dd, -1, DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) + 1, 0)) AS MthEndDate ,
        DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0) AS YearStartDate ,
        DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1) AS YearEndDate;

Open in new window

0
Comment
Question by:mburk1968
3 Comments
 
LVL 66

Expert Comment

by:Jim Horn
ID: 41762632
Sounds like a candidate for building your own SQL Server Calendar Table, where you can add logic for custom seasons like Fiscal Years here.  

That way instead of having to code a big honkin' expression every time you want to query season-to-date, just code it once when you build the table in order to populate season-specific columns.  Then you can do a simple JOIN in query expressions.
0
 
LVL 41

Accepted Solution

by:
Sharath earned 2000 total points
ID: 41763863
May be something like this. try this.
SELECT  DATEADD(wk, 0,
                DATEADD(DAY, 1 - DATEPART(WEEKDAY, GETDATE()),
                        DATEDIFF(dd, 0, GETDATE()))) AS WkStartDate ,
        DATEADD(wk, 1,
                DATEADD(DAY, 0 - DATEPART(WEEKDAY, GETDATE()),
                        DATEDIFF(dd, 0, GETDATE()))) AS WkEndDate ,
        DATEADD(mm, DATEDIFF(mm, 0, GETDATE()), 0) AS MthStartDate ,
        DATEADD(dd, -1, DATEADD(mm, DATEDIFF(mm, 0, GETDATE()) + 1, 0)) AS MthEndDate ,
        DATEADD(yy, DATEDIFF(yy, 0, GETDATE()), 0) AS YearStartDate ,
        DATEADD(yy, DATEDIFF(yy, 0, GETDATE()) + 1, -1) AS YearEndDate,
        CASE WHEN REPLACE(CONVERT(VARCHAR(5),GETDATE(),1),'/','') <= '0630' THEN '0101' ELSE '0701' END AS STDStartDate,
        CASE WHEN REPLACE(CONVERT(VARCHAR(5),GETDATE(),1),'/','') <= '0630' THEN '0630' ELSE '1231' END AS STDEndDate;

Open in new window

0
 

Author Closing Comment

by:mburk1968
ID: 41765447
Thank you
0

Featured Post

Keep up with what's happening at Experts Exchange!

Sign up to receive Decoded, a new monthly digest with product updates, feature release info, continuing education opportunities, and more.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

I have written a PowerShell script to "walk" the security structure of each SQL instance to find:         Each Login (Windows or SQL)             * Its Server Roles             * Every database to which the login is mapped             * The associated "Database User" for this …
Ever needed a SQL 2008 Database replicated/mirrored/log shipped on another server but you can't take the downtime inflicted by initial snapshot or disconnect while T-logs are restored or mirror applied? You can use SQL Server Initialize from Backup…
The Relationships Diagram is a good way to get an overall view of what a database is keeping track of. It is also where relationships are defined. A relationship specifies how two tables connect to each other. As you build tables in Microsoft Ac…
Kernel Data Recovery is a renowned Data Recovery solution provider which offers wide range of softwares for both enterprise and home users with its cost-effective solutions. Let's have a quick overview of the journey and data recovery tools range he…

564 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question