troubleshooting Question

PHP Contents of select statement stored in Array and used in Dropdown Menu

Avatar of stkoontz
stkoontzFlag for United States of America asked on
PHP
5 Comments1 Solution71 ViewsLast Modified:
I'd like to store the output of an SQL select statement into an array, then use that array to populate a dropdown menu.  

I'm using $result = $sth->fetchAll(); to store the contents of 2 fields into the array. Which comes out looking like this...

Array
(
    [0] => Array
        (
            [id_event_group] => uh
            [0] => uh
            [event_group_desc] => Urban Hope
            [1] => Urban Hope
        )

    [1] => Array
        (
            [id_event_group] => mo
            [0] => mo
            [event_group_desc] => Momentum
            [1] => Momentum
        )

)

When I use the following code to create the dropdown, I just get 'array' 'array' as the options.

echo '<select name="event groups">';
echo '<option value="">Select...</option>';
foreach ($my_array as $k => $v) {
	echo '<option value="' . $k . '">' . $v . '</option>';
}
echo '</select>';

If it helps, here's a link to the page.

http://testregister.cenational.org/test/test1.php

Thanks in advance for giving me a hand.

Steve
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