# Of Years Calculation

Hi there,

I am attempting to calculate consecutive years in the attached file - for each year of activity the value is "1" if no activity the value is 0.

From Right to left (2015 to 1987) if there is a value of 1 then continue to move to the next column to the left.  If the value is 0 then return the column header year and discontinue any calculations.

Attached is the file layout - let me know if there are any questions on what I am asking.  I usually do this in crystal reports but am hoping to get away from the labour-intensive setup.

Thanks very much - CS
EE-Sample.xlsx
rporter45Asked:
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Subodh Tiwari (Neeraj)Connect With a Mentor Excel & VBA ExpertCommented:
If you are trying to return the header year from the right where it encounters the first zero, you may try this.....

On Row2 of a blank column
=INDEX($B$1:$AD$1,MAX(INDEX((B2:AD2=0)*(COLUMN($B$1:$AD$1)-COLUMN($B$1)+1),)))

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And if you are interested in header year where the last consecutive 1 is found from the right, try this...
=INDEX($B$1:$AD$1,MAX(INDEX((B2:AD2=0)*(COLUMN($B$1:$AD$1)-COLUMN($B$1)+1),))+1)

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Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
Are you trying to calculate col. AG?
If so, you may use the following formula to get the desired output in col. AG...
=COUNTIF(B2:AD2,1)

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and copy down.
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Rob HensonFinance AnalystCommented:
The way I read your question is that you are trying to find the most recent year of inactivity.

ID      Year
100   1997
200   1996
300   1996
etc

Is that correct? Not sure how you would do it with current layout.

Thanks
Rob
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Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
@Rob
That is what the first of the two formulas from my previous post does. :)
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Rob HensonFinance AnalystCommented:
@Neeraj - I hadn't refreshed while entering my comment so didn't see your post. I was posting to confirm interpretation of the question. If our interpretation is correct then hopefully your solution will be what is required.

Thanks
Rob
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Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
No Problem Rob!
Actually your post confirmed that I was thinking in the right direction. :)
Now it's up to OP to confirm whether this was the original request.
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rporter45Author Commented:
This worked perfectly! Saves me a ton of time - very much appreciated,

Have a great day,
Colleen
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Subodh Tiwari (Neeraj)Excel & VBA ExpertCommented:
You're welcome. Glad to help.
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