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Find characters between pattern in a file linux

Posted on 2016-09-01
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Last Modified: 2016-09-01
I have a file containing data like

10.222.3.124 - - [31/Aug/2016:00:00:00 +0100] DELETE /artefacts/content/repositories/trs-uta-releases/com/ac/fm/sc/arsing/arsing-du/1.0.4.22/ HTTP/1.1 204 -

I wan to list characters falling between "repositories/" and "/"
like in above example , it should give me
trs-uta-releases   only
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Question by:Ravi Raj
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woolmilkporc earned 500 total points
ID: 41779559
STR='10.222.3.124 - - [31/Aug/2016:00:00:00 +0100] DELETE /artefacts/content/repositories/trs-uta-releases/com/ac/fm/sc/arsing/arsing-du/1.0.4.22/ HTTP/1.1 204 -'

echo $STR |  sed -e 's/^.*repositories\///' -e 's/\/.*//'

alternatively:

echo $STR | sed -e 's/^.*repositories\/\([^\/]*\).*/\1/'
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Author Comment

by:Ravi Raj
ID: 41779565
Awesome , It worked for me, Ta!
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Author Closing Comment

by:Ravi Raj
ID: 41779568
Awesome Solution
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