Create multiple files from one files

     foreach($new_files as $new_file) {
                    //create file
                	$myfile = fopen($filename, "w");
   
                    //put contents in the file               	
                	fwrite($filename, $new_file['content']);	
              		//close the file
                	fclose($myfile);
                }

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I have this code to create a new file, I want to be able to open $filename, and create multiple files from it
This code doesnt seem to work, any ideas?
LVL 1
Jazzy 1012Asked:
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Marco GasiConnect With a Mentor FreelancerCommented:
Sorry, I've jut realized your code is wrong:
fwrite($filename, $new_file['content']);

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should be:
fwrite($myfile, $new_file['content']);

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But give a different filename to your files. I used thi code:
$new_files = array(
		array(
				"name" => "3650.5010.16231a_4",
				"content" => "IS*00*          *00* 
gfhfidfioghio
dfgjkhguidf
kfjghjdgfuighuigt
489764896hj      
gfhfidfioghio
dfgjkhguidf
kfjghjdgfuighuigt
489764896hj"),
		array(
				"name" => "3650.5010.16231a_5",
				"content" => "IA5765897
dghertughfh
457885639057
764769487634
457659639486
fhfidhfh
dghertughfh
457885639057
764769487634
457659639486
fhfidhfh"
		)
);

foreach ($new_files as $new_file) {
	$filename =  $new_file['name'].'.txt';
	//create file
	$myfile = fopen($filename, "w");
	//put contents in the file               	
	fwrite($myfile, $new_file['content']);
	//close the file
	fclose($myfile);
}

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0
 
Marco GasiFreelancerCommented:
What is the criterion to split the original file in other files? Or you just want to replicate the whole content of the original file in several different files?

In general, if you want to split a file in several smaller files you can use file() function to create an array from a file: each line will become an array item; then you can iterate through the array to get content blocks and save them in another file following your specific criteria.
1
 
Jazzy 1012Author Commented:
When I print_r() new files , I get the content i did for example:
Array
(
    [0] => Array
        (
            [name] => 3650.5010.16231a_4
            [content] => IS*00*          *00*    
gfhfidfioghio
dfgjkhguidf
kfjghjdgfuighuigt
489764896hj      
gfhfidfioghio
dfgjkhguidf
kfjghjdgfuighuigt
489764896hj      
 [1] => Array
        (
            [name] => 3650.5010.16231a_5
            [content] => IA5765897
dghertughfh
457885639057
764769487634
457659639486
fhfidhfh
dghertughfh
457885639057
764769487634
457659639486
fhfidhfh


Thats how I want it but each array in a seperate file, however thats not how it comes out
0
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Ray PaseurCommented:
Please use var_export() to print out variables that you want us to work with.  Then you will get a code representation that you can post in the code snippet here at E-E.  Much more useful than print_r()!  This will save us (and you) a lot of time!
0
 
Marco GasiFreelancerCommented:
Okay, now I understand. I suppose you're creating only one file: if this is the case, the problem is that you foreach file you use the same file name ($filename): so you are overwriting the same file content.
Give me a minute to test.
0
 
Ray PaseurCommented:
Please see: https://iconoun.com/demo/temp_jasmine_4.php
<?php // demo/temp_jasmine_4.php
/**
 * https://www.experts-exchange.com/questions/28967752/Create-multiple-files-from-one-files.html
 */
error_reporting(E_ALL);
echo '<pre>';


$data = Array
( 0 => [
  'name' => '3650.5010.16231a_4'
, 'content' => 'IS*00*          *00*
gfhfidfioghio
dfgjkhguidf
kfjghjdgfuighuigt
489764896hj
gfhfidfioghio
dfgjkhguidf
kfjghjdgfuighuigt
489764896hj' ]
, 1 => [
  'name' => '3650.5010.16231a_5'
, 'content' => 'IA5765897
dghertughfh
457885639057
764769487634
457659639486
fhfidhfh
dghertughfh
457885639057
764769487634
457659639486
fhfidhfh' ]
)
;

// DOES IT LOOK RIGHT?  YES
var_export($data);
echo PHP_EOL;

// THE DIRECTORY TO HOLD THE FILES
$dir = 'storage';

// WRITE ONE FILE FOR EACH INTERNAL ARRAY
foreach ($data as $thing)
{
    $path = $dir . DIRECTORY_SEPARATOR . $thing['name'];
    file_put_contents($path, $thing['content']);
}

// SHOW LINKS SO WE CAN VERIFY THE CONTENT OF THE FILES
foreach ($data as $thing)
{
    $path = $dir . DIRECTORY_SEPARATOR . $thing['name'];
    $link = '<a target="_blank" href="' . $path . '">' . $thing['name'] . '</a>' . PHP_EOL;
    echo $link;
}

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1
 
Ray PaseurCommented:
@Jasmine: Did you test the code posted here?  What was wrong with the answer?
0
 
Jazzy 1012Author Commented:
It wasn't wrong but I just had to changed my variable for my code to work
0
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