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Your approach is done in a straightforward conventional way. Looks good.
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Can you please explain the part 1 that how the values of x and y are plugged in
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y = y(x) = 2^(-x) = 1/2^(x)<br />
Using your sample values of x:<br />
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y(1) = 1/2^(1) = 1/2 &nbsp; &nbsp; &nbsp; &nbsp; ==&gt; (1, 1/2)<br />
y(0) = 1/2^(0) = 1/1 = 1 &nbsp; ==&gt; (0,1)<br />
y(-1) = 1/2^(-1) = 1/ (1/2) = 2 ==&gt; (-1, 2) &nbsp; &nbsp; // I see that you had (-1, 1/2) even though you had y=2
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For part 2, you can graph the two curves, i.e., the quadratic and the straight lines, and then get an approximation of g(x).<a href="https://filedb.experts-exchange.com/incoming/2016/09_w37/1115342/graph_2_curves.png" target="_blank" title="graph_2_curves.png (8 KB)"><img alt="graph_2_curves.png" class="file-block lazyload" style="max-width: 800px;" data-src="https://filedb.experts-exchange.com/incoming/2016/09_w37/800_1115342/graph_2_curves.png" /></a><a href="https://filedb.experts-exchange.com/incoming/2016/09_w37/1115344/graph_2_curves_zoom1.png" target="_blank" title="graph_2_curves_zoom1.png (8 KB)"><img alt="graph_2_curves_zoom1.png" class="file-block lazyload" style="max-width: 800px;" data-src="https://filedb.experts-exchange.com/incoming/2016/09_w37/800_1115344/graph_2_curves_zoom1.png" /></a>From the graphs, you can get a rough feel where the intersections of the two graphs are. Then you guess and compute g(x_guess). Then you increment and decrement x_guess by, say, 0.1, and see which g(x) is closer to -8. Now you have a new x_guess. and you modify x_guess by 0.5 in both directions to chose a new x_guess. Keep doing this until the new x_guess is the same as the previous one for the desired number of decimal places.
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Can you please explain it in a different way?<br />
<a href="https://filedb.experts-exchange.com/incoming/2016/09_w37/1115338/q12.JPG" target="_blank" title="q12.JPG (35 KB)"><img alt="q12.JPG" class="file-block lazyload" style="max-width: 800px;" data-src="https://filedb.experts-exchange.com/incoming/2016/09_w37/800_1115338/q12.JPG" /></a><a href="https://filedb.experts-exchange.com/incoming/2016/09_w37/1115339/q13.JPG" target="_blank" title="q13.JPG (17 KB)"><img alt="q13.JPG" class="file-block lazyload" style="max-width: 592px;" data-src="https://filedb.experts-exchange.com/incoming/2016/09_w37/1115339/q13.JPG" /></a><a href="https://filedb.experts-exchange.com/incoming/2016/09_w37/1115340/screenshot3.jpg" target="_blank" title="screenshot3.jpg (7.3 MB)"><img alt="screenshot3.jpg" class="file-block lazyload" style="max-width: 800px;" data-src="https://filedb.experts-exchange.com/incoming/2016/09_w37/800_1115340/screenshot3.jpg" /></a>
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Can you please explain it in a different way?




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