Link to home
Create AccountLog in
Avatar of mustish1
mustish1

asked on

Graph Function

Can you please explain it in a different way?
User generated imageUser generated imageUser generated image
Avatar of phoffric
phoffric

Your approach is done in a straightforward conventional way. Looks good.
Avatar of mustish1

ASKER

Can you please explain the part 1 that how the values of x and y are plugged in
y = y(x) = 2^(-x) = 1/2^(x)
Using your sample values of x:

y(1) = 1/2^(1) = 1/2         ==> (1, 1/2)
y(0) = 1/2^(0) = 1/1 = 1   ==> (0,1)
y(-1) = 1/2^(-1) = 1/ (1/2) = 2 ==> (-1, 2)     // I see that you had (-1, 1/2) even though you had y=2
For part 2, you can graph the two curves, i.e., the quadratic and the straight lines, and then get an approximation of g(x).User generated imageUser generated imageFrom the graphs, you can get a rough feel where the intersections of the two graphs are. Then you guess and compute g(x_guess). Then you increment and decrement x_guess by, say, 0.1, and see which g(x) is closer to -8. Now you have a new x_guess. and you modify x_guess by 0.5 in both directions to chose a new x_guess. Keep doing this until the new x_guess is the same as the previous one for the desired number of decimal places.
ASKER CERTIFIED SOLUTION
Avatar of phoffric
phoffric

Link to home
membership
Create a free account to see this answer
Signing up is free and takes 30 seconds. No credit card required.
See answer
Thank You.