asked on

java continue statement

Hi,

https://docs.oracle.com/javase/tutorial/java/nutsandbolts/branch.html

package com.solution;

class ContinueDemo {
    public static void main(String[] args) {

        String searchMe = "peter piper picked a " + "peck of pickled peppers";
        int max = searchMe.length();
        int numPs = 0;

        for (int i = 0; i < max; i++) {
            // interested only in p's
            if (searchMe.charAt(i) != 'p')
                continue;

            // process p's
            numPs++;
        }
        System.out.println("Found " + numPs + " p's in the string.");
    }
}

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Found 9 p's in the string.

How below printed 35 when i comment continue where as above printed 9

package com.solution;

class ContinueDemo {
    public static void main(String[] args) {

        String searchMe = "peter piper picked a " + "peck of pickled peppers";
        int max = searchMe.length();
        int numPs = 0;

        for (int i = 0; i < max; i++) {
            // interested only in p's
            if (searchMe.charAt(i) != 'p')
               // continue;

            // process p's
            numPs++;
        }
        System.out.println("Found " + numPs + " p's in the string.");
    }
}

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Found 35 p's in the string.

peter piper picked a " + "peck of pickled peppers

when i counted above it has 49 characters including spaces though

please advise

ASKER CERTIFIED SOLUTION

CPColin

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gudii9

ASKER

So your code is counting every character that isn't a P.

including free space?

gudii9

ASKER

peter piper picked a " + "peck of pickled peppers

when i count i am counting as 40 manually though. which also matches below calculation
as 49-9=40

CPColin

Don't count the " + " characters; they're not part of the string. (Print it out and see.)

SOLUTION

rrz

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gudii9

ASKER

package com.solution;

class ContinueDemo {
    public static void main(String[] args) {

        String searchMe = "peter piper picked a " + "peck of pickled peppers";
        int max = searchMe.length();
        int numPs = 0;

        for (int i = 0; i < max; i++) {
            // interested only in p's
            if (searchMe.charAt(i) != 'p')
               // continue;

            // process p's
            numPs++;
        }
        System.out.println("max is " + max);
        System.out.println("Found " + numPs + " p's in the string.");
    }
}

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max is 44
Found 35 p's in the string.

i wonder why max says 44 so 44 is 35 plus 9(ie nine P's) total 44 of all characters without +?

why they used + in the below String
peter piper picked a " + "peck of pickled peppers
just to show String concatenation?

CPColin

Probably.

gudii9

ASKER

" + "

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even space before and after plus also i should not count to get 44 looks.

Otherwise count coming around 47

CPColin

Print the searchMe string and count the characters. The plus sign and the spaces are not part of the string; they're Java syntax.

gudii9

ASKER

Print the searchMe string and count

right that is max which is 44 .

 for (int i = 0; i < max; i++) {
            // interested only in p's
            if (searchMe.charAt(i) != 'p')
               // continue;

            // process p's
            numPs++;
        }

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above code technically mean

 for (int i = 0; i < max; i++) {
            // interested only in p's
        //    if (searchMe.charAt(i) != 'p')
               // continue;

            // process p's
            numPs++;
        }

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as we are checking searchMe.charAt(i) != 'p' but them adding numPs by one as continue not there to skip that particular iteration of for loop