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mustish1

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Graph function

Can you please tell me how f(0), f(1), f(2).... is calculated?
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Sean Stuber

substitute the value for the variable and complete the arithmetic

f(x) = -0.8x(x-9)

so f(0) = -0.8*0(0-9)= 0(-9) =0

f(1) = -0.8*1(1-9) = -0.8(-8) = 6.4

and so on
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Can you please also explain the part B
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Sean Stuber

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