Solved

How can I show or hide div with radio button and jQuery, and process on page load?

Posted on 2016-09-07
4
72 Views
Last Modified: 2016-09-07
I am using the below code to show or hide a div with jQuery. It works fine on the first visit, but if a person hits the back button and visits the page while the "ShowIt" radio button is selected, it will be hidden, because it's hidden by default. How can i make it show if the ShowIt radio is selected when the page loads? Thank you!

	$(document).ready(function(){
		$('#myDiv').hide();
	    $('input[type="radio"]').click(function(){
	        if($(this).attr("value")=="HideIt"){
	            $('#myDiv').hide('fast');
	        }
	        if($(this).attr("value")=="ShowIt"){
	            $('#myDiv').show('fast');
	        }	
	    });
	});

Open in new window

0
Comment
Question by:earwig75
  • 2
4 Comments
 
LVL 43

Expert Comment

by:zephyr_hex (Megan)
ID: 41788316
You can look for the checked status of the radio and show the div if it's checked:

if ($('#ShowIt').is(':checked')) {
  $('#myDiv').show();
}

Open in new window


Here is a Fiddle Demo.
0
 
LVL 55

Accepted Solution

by:
Julian Hansen earned 500 total points
ID: 41788382
Another option
if ($('input:checked').val() == 'ShowIt') {
  $('#myDiv').show('fast');
}

Open in new window

Here is the complete code - I am assuming you have given your radio's a name attribute to group them - I have used that in the code to target the click as well
<script>
$(function() {
  if ($('input:checked').val() == 'ShowIt') {
    $('#myDiv').show('fast');
  }
  
  $('input[name="toggle"]').click(function() {
  if ($(this).val() == 'ShowIt') {
    $('#myDiv').show();
  }
  else {
    $('#myDiv').hide();
  }
  });
});
</script>

Open in new window

Working sample here

EDIT:
HTML used for above sample
    <input type="radio" name="toggle" value="ShowIt" /> Show <input type="radio" name="toggle" value="HideIt" /> Hide <br/>
    <div id="myDiv" style="display: none" >This is my div</div>

Open in new window

0
 

Author Closing Comment

by:earwig75
ID: 41788446
Ignore my last comment, this works perfectly, thank you.
0
 
LVL 55

Expert Comment

by:Julian Hansen
ID: 41788452
You are welcome.
0

Featured Post

Master Your Team's Linux and Cloud Stack!

The average business loses $13.5M per year to ineffective training (per 1,000 employees). Keep ahead of the competition and combine in-person quality with online cost and flexibility by training with Linux Academy.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Introduction A frequently asked question goes something like this:  "I am running a long process in the background and I want to alert my client when the process finishes.  How can I send a message to the browser?"  Unfortunately, the short answer …
PROBLEM: The other day I was working on adding an ajax request to a webpage that already had a dialog box on the page.  The dialog box was using relative positioning to be positioned next to a form field I had on the page.  Everything was working…
The viewer will learn how to dynamically set the form action using jQuery.
The viewer will learn the basics of jQuery including how to code hide show and toggles. Reference your jQuery libraries: (CODE) Include your new external js/jQuery file: (CODE) Write your first lines of code to setup your site for jQuery…

820 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question