Linq Query Add new object array

Hi

I had question on this Refactor C# code.

How do I query this if we have more than Single record for SalesOrderType(Mapping SubDocuments.Attributes) sepertaed by "$,$"

E.g. if we have document.attributes[0 ].value as below
Note we have 2 records in this  separated by $,$

1**10**New Client**2016-11-02**250**10-F0040Z$$10-F0040Z$$10-F00141$,$1W**New Client - Add2 Product**2016-11-02**250**1W-F71900$$1W-F0070X


     req.salesOrders = (from document in resp.transaction.quote_data.sub_documents
                                   let values = document.attributes[0].value.ToString().Split(new[] { "**" }, StringSplitOptions.None)
                                   where (document.attributes != null && document.attributes.Length > 0) && !string.IsNullOrWhiteSpace(document.attributes[0].value.ToString()) && !string.IsNullOrEmpty(values[3]) && (!string.IsNullOrWhiteSpace(values[5]) && values[5] != "$$")
                                   select new salesOrder()
                                   {
                                       productCode = values[1],
                                       salesOrderType = values[2],
                                       startDate = DateTime.Parse(values[3]).ToString("yyyy-MM-dd"),
                                       pays = !string.IsNullOrWhiteSpace(values[4]) ? int.Parse(values[4]) : 0,
                                       scns = (from code in values[5].Split(new[] { "$$" }, StringSplitOptions.RemoveEmptyEntries)
                                               select
                                               new scns()
                                               {
                                                   scnCode = code
                                               }).GroupBy(o => o.scnCode).Select(g => g.First()).ToList()

                                   }).ToList() ;
Member_2_7967608Asked:
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Fernando SotoRetiredCommented:
Hi;

Linq query like this will do what you want. You will need to implement it to your code.
string[] documents = {"1**10**New Client**2016-11-02**250**10-F0040Z$$10-F0040Z$$10-F00141$,$1W**New Client - Add2 Product**2016-11-02**250**1W-F71900$$1W-F0070X",
			"1**10**New Client**2016-11-02**250**10-F0040Z$$10-F0040Z$$10-F00141$,$1W**New Client - Add2 Product**2016-11-02**250**1W-F71900$$1W-F0070X" };              
                                                                                                                                                                   
var result = (from string d in documents                                                                                                                           
              let docArray = Regex.Split(d, @"\$,\$")                                                                                                                    
              let value = docArray.Select(v => v.Split(new[] { "**"}, StringSplitOptions.RemoveEmptyEntries))                                                            
              select value).ToList();             

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The results of this code is.Resulta
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Member_2_7967608Author Commented:
The issue here is one row can be an array split by $,$ as below

1**10**New Client**2016-11-02**250**10-F0040Z$$10-F0040Z$$10-F00141$,$1**,1W**New Client - Add2 Product**2016-11-02**250**1W-F71900$$1W-F0070X

the second row can be as below with no $,$  

1**99**New Client**2016-11-02**250**10-F0040Z$$10-F0040Z$$10-F00141
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Fernando SotoRetiredCommented:
Yes, take a close look at the results I posted you will see each input line gets split into two records for each line.
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Member_2_7967608Author Commented:
There is case where a row does not have '$,$'. Will it query this record.

1**99**New Client**2016-11-02**250**10-F0040Z$$10-F0040Z$$10-F00141
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Fernando SotoRetiredCommented:
A single record in one string worked for me, I used this as input.
string[] documents = {"1**10**New Client**2016-11-02**250**10-F0040Z$$10-F0040Z$$10-F00141" };

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Member_2_7967608Author Commented:
Thanks Fernando.
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Member_2_7967608Author Commented:
Thanks Fernando, One thing I needed was  to eliminate duplicates in the output list req.salesOrders  for  salesOrder.productCode

Example req.salesOrders  should have single record for req.salesOrders=10  (product) this should be unique.   All the req.scns


> 1**10**New Client**2016-11-02**250**F0040Z$$F0040Z$$F00141$,$1**,1W**New Client - Add2 Product**2016-11-02**250**F71900$$F0070X

> 1**10**New Client**2016-11-02**250**F00498$$F00493$$F00141

Example in above it should return
{
productCode = 10
 salesOrderType =New Client,
 startDate = '2016-11-02',
 pays = 250
 scns = {F0040Z,F00141, F00498,F00493}  //removed dups . this is implemented
}
{
productCode = 1W
 salesOrderType =New Client - Add2 Product,
 startDate = '2016-11-02',
 pays = 250
 scns = { F71900,F0070X}
}

The DTOs of this question are in the link below.  I was not sure if we can implement in the same link.

https://www.experts-exchange.com/questions/28958730/Refactor-C-code.html
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Fernando SotoRetiredCommented:
Hi;

A couple of things. First EE likes only to have one question per thread with followup questions relating to the original question posted. Because your last post does not relate to the original question please open a new question for it and I will be happy to look at it. Secondly what do you mean by duplicates? For example in req.salesOrders you have five fields, do ALL fields of a record have to be exactly the same or only some or one fields be the same for it to be a duplicate?
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Member_2_7967608Author Commented:
Sorry about it , I was not aware about it.  I put it since it was very much related. I can open new question if u want to.

In the output  list req.saleorders we have remove duplicates by productCode.
In the below example it is value[1] 10, 1W.

req.salesorders should be unique on the value[1] field

> 1**10**New Client**2016-11-02**250**F0040Z$$F0040Z$$F00141$,$1**,1W**New Client - Add2 Product**2016-11-02**250**F71900$$F0070X

> 1**10**New Client**2016-11-02**250**F00498$$F00493$$F00141

Thanks in advance
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Fernando SotoRetiredCommented:
Yes, please open a new question. Thank you.
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