Solved

# Counting in sql

Posted on 2016-09-08
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Hi All

I'm trying to do something which might come down to logic, but I think mostly comes down to not knowing how to write it in an sql query.  I've attached a sheet from Excel so that I can explain what I mean.

I need to figure out a way to count the number of different personal_id's per SSN e.g. for THES06001750Y there will be 2.  In my whole data, some may only have one and some could have many, many more.  I need this number so that I can divide into another value later on as it's to do with duplicates.  I can't just do something clever with duplicates because I probably don't know how but mainly because I won't be able to access the other data, summarize both sets of data and track differences in the way I need.

I've had a couple of goes and the best (?!!!!) one so far seems to be to create a table based on distinct personal_id's, get the SSNs and then, in the main table, which has all the first set of data in it, add a column and try to join the tables with some kind of count.  In the vain hope that today might be my lucky day, I tried the following:

UPDATE A SET PI_Counts = B.COUNT (personal_id)
FROM LFRD A LEFT OUTER JOIN LFRD_PI_Count B ON A.SSN = B.PI_SSNs;

I didn't really think it would work and, of course it didn't!

Please can somebody help me figure out a way to do this?

Thanks
Sarah
EE_Count_Example.xlsx
0
Question by:ScuzzyJo
• 3
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• 2

LVL 42

Expert Comment

ID: 41789704
Here's one way to do it:

``````SELECT  COUNT(personal_id) AS cnt ,
ssn
FROM    ( SELECT    personal_id ,
ssn
FROM      #tmp_test
GROUP BY  personal_id ,
ssn
) c
GROUP BY ssn;
``````

I first get the distinct records from the table (using grouping), then do the count
0

LVL 42

Accepted Solution

zephyr_hex earned 400 total points
ID: 41789722
And I believe your update will look like:

``````UPDATE A SET A.PI_Counts = COUNT(c.personal_id)
FROM LFRD A
INNER JOIN (
SELECT personal_id, ssn
FROM      #tmp_test
GROUP BY  personal_id, ssn
) c ON c.ssn = A.ssn
GROUP BY c.ssn
``````
0

Author Comment

ID: 41789744
Hi Zeyphyr_hex

Thanks, am trying it now, but how do I get the results into a table?  I know I'm going to put "into" somewhere but I'm not sure where.

Thanks
Sarah
0

LVL 18

Assisted Solution

Pawan Kumar Khowal earned 100 total points
ID: 41789764
Below will insert the result set in to a temp table

``````SELECT  COUNT(personal_id) AS cnt ,
ssn
INTO #Temp
FROM    ( SELECT    personal_id ,
ssn
FROM      #tmp_test
GROUP BY  personal_id ,
ssn
) c
GROUP BY ssn;
``````
0

Author Comment

ID: 41789782
Hi

Stupid me!  I knew that - where to put the into bit.

Your solution works perfectly.  Thanks for your help.

Thanks
Sarah
0

Author Closing Comment

ID: 41789785
Really quick and good answers.  Thanks to both of you.
0

LVL 18

Expert Comment

ID: 41789790
Welcome :)
0

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