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Regular expression that only finds last instance
Posted on 2016-09-09
If I have strings such as these:
1. AB-123
2. AB 123
3. AB-123-1
4. AB 123-1
5. AB XYZ-1
I need a regular expression that determine if the end contains /\-\d+$/ and only #3, #4, and #5 to qualify.
The problem I'm running into is that the above regex matches for #1, #3, #4, and #5 since they all have hyphens.
If there's a nice regex that can be used to solve this, that would be great. Otherwise, I'm open to javascript, such as using the split function. I've been trying that unsuccessfully, too.
var splitter = str.split(/\-\d+$/)
I just don't have a good way to tell if the string qualifies with /\-\d+$/ when there are possible hyphen instances earlier in the string.
1. AB-123
2. AB 123
3. AB-123-1
4. AB 123-1
5. AB XYZ-1
I need a regular expression that determine if the end contains /\-\d+$/ and only #3, #4, and #5 to qualify.
The problem I'm running into is that the above regex matches for #1, #3, #4, and #5 since they all have hyphens.
If there's a nice regex that can be used to solve this, that would be great. Otherwise, I'm open to javascript, such as using the split function. I've been trying that unsuccessfully, too.
var splitter = str.split(/\-\d+$/)
I just don't have a good way to tell if the string qualifies with /\-\d+$/ when there are possible hyphen instances earlier in the string.
[X]
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1 Comment
Assuming that 1., 2., 3., 4., 5. at the beginning of each example and the spaces after them are not part of the search string but the new line at the end of each line is, the following should work for a test condition.
/(\s|-)[\da-z]+-\d+$/
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