Get more info about an IP address or domain name, such as organization, abuse contacts and geolocation.
One of a set of tools we are providing to everyone as a way of saying thank you for being a part of the community.
So even bunnies has 2 ears and odd ones have 3 ears and we have to return total ears?
Recursion-1 > bunnyEars2
prev | next | chance
We have bunnies standing in a line, numbered 1, 2, ... The odd bunnies (1, 3, ..) have the normal 2 ears. The even bunnies (2, 4, ..) we'll say have 3 ears, because they each have a raised foot. Recursively return the number of "ears" in the bunny line 1, 2, ... n (without loops or multiplication).
bunnyEars2(0) → 0
bunnyEars2(1) → 2
bunnyEars2(2) → 5