<div>
You could try &quot;basename&quot;, a utility exactly meant for that purpose:<br />
<br />

<pre><code class="code-1 nolinks" id="code-20-41794877-1"><span>find /mnt/ABC_POOL/ABC_BUILD/ -type f -name .zip -prune -o -mmin -5 -type f -print | while read file</span>
<span>  do</span>
<span>    echo $(basename $file)</span>
<span>  done</span>
</code></pre>
<br />
If the result of the find command is <b>always just one</b> filename you could put it like this:<br />
<br />

<pre><code class="code-1 nolinks" id="code-20-41794877-2"><span>FILE=$(basename $(find /mnt/ABC_POOL/ABC_BUILD/ -type f -name .zip -prune -o -mmin -5 -type f -print))</span>
</code></pre>
</div>


<div>
Awesome, that works perfectly.<br />
<br />
much appreciated.<br />
<br />
Regards,<br />
Atorex
</div>


<div>
You can of course use &quot;awk&quot;, because &quot;awk&quot; can do just <i>everything</i>:<br />
<br />

<pre><code class="code-1 nolinks" id="code-20-41794896-1"><span>find /mnt/ABC_POOL/ABC_BUILD/ -type f -name .zip -prune -o -mmin -5 -type f -print | awk '{F=split($0,A,&quot;/&quot;); print A[F]}'</span>
</code></pre>
</div>


<div>
I have completed my script, thanks to you woolmilkporc, I have one issue I just noticed, the output is listing all files in sequence with a space separating each file, is there a way to have the output of the command I'm using to list it all like ls -l would in a column? <br />
here is my command as a variable, I use the output of the variable to email the list of files.<br />
<br />
FILE=$(basename $(find /mnt/ABC_POOL/ABC_BUILD/ -type f -newerct '5 minute ago' -print))<br />
<br />
<br />
Regards,<br />
Atorex
</div>


<div>
How do you use the variable?<br />
<br />
If it's something like <br />
<br />
echo $FILE | mailx ... ...<br />
<br />
you can try <br />
<br />
echo $FILE | tr &quot;&nbsp;&quot; &quot;\n&quot; | mailx... ...<br />
<br />
If you're using a different approach please let me know .
</div>


<div>
yes I'm using echo $FILE in to a temp file to be used for the body of the email like.<br />
<br />
echo $FILE &gt;&nbsp;/mnt/ABC_POOL/ABC_BUILD/ne<wbr />wfile<br />
<br />
so the below should work?<br />
<br />
echo $FILE | tr &quot;&nbsp;&quot; &quot;\n&quot; &gt;&nbsp;/mnt/ABC_POOL/ABC_BUILD/ne<wbr />wfile
</div>


<div>
Yes, but if you want the output to go to a file you can simply do this:<br />
<br />

<pre><code class="code-1 nolinks" id="code-20-41796684-1"><span>find /mnt/ABC_POOL/ABC_BUILD/ -type f -newerct '5 minute ago' -print | xargs -n1 basename &gt; /mnt/ABC_POOL/ABC_BUILD/newfile</span>
</code></pre>
</div>


<div>
Ok, i'm using the variable to validate if a file is found in an if statement, the validation I'm using is<br />
if [ -s $FILE ] and has been working so far. <br />
Thanks for your help, trying to better my limited bash &nbsp;scripting &nbsp;capabilities.<br />
<br />
<br />
Regards,<br />
Atorex
</div>


<div>
<div class="content wysiwyg-content">
I'm working on a script to locate newly changed files and send out an email, I need help pulling just the file name from the resulting find command.<br />
<br />
my find command is-<br />
find /mnt/ABC_POOL/ABC_BUILD/ -type f -name .zip -prune -o -mmin -5 -type f -print<br />
the result from the above would be something like this<br />
<br />
/mnt/ABC_POOL/ABC_BUILD/XS<wbr />TORE/ELC/A<wbr />BC_xyz_7.1<wbr />.4.17_1.12<wbr />.3-install<wbr />x.zip<br />
I would like to use just the zip file name as my final result by using awk or sed to remove the path and leave just the file name, keeping in mind that the full path is not always the same. <br />
I'm hoping there is a way to remove everything from start of string leaving the last part after the last / that would be the file name.<br />
<br />
Any idea what would be the best way, I attempted awk -F&quot;\t&quot; but did not work.
</div>
</div>


I'm working on a script to locate newly changed files and send out an email, I need help pulling just the file name from the resulting find command.

my find command is-
find /mnt/ABC_POOL/ABC_BUILD/ -type f -name .zip -prune -o -mmin -5 -type f -print
the result from the above would be something like this

/mnt/ABC_POOL/ABC_BUILD/XSTORE/ELC/ABC_xyz_7.1.4.17_1.12.3-installx.zip
I would like to use just the zip file name as my final result by using awk or sed to remove the path and leave just the file name, keeping in mind that the full path is not always the same. 
I'm hoping there is a way to remove everything from start of string leaving the last part after the last / that would be the file name.

Any idea what would be the best way, I attempted awk -F"\t" but did not work.

help pulling data string using Awk

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