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Powershell - Check two AD groups and show difference

Posted on 2016-09-15
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Last Modified: 2016-09-16
Hi EE

Can someone help me with a script ? I need to check groupA and groupB and show the difference in users from both.

So if groupA has 50 users , groupB has 40 , for it to export " 10 " or "10 missing accounts"
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Question by:MilesLogan
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6 Comments
 
LVL 40

Expert Comment

by:Subsun
ID: 41800379
Try..
Function Check-GroupDiff ($GroupA,$GroupB){
Compare (Get-AdGroupMember $GroupA -Recursive | 
Select -ExpandProperty SamAccountName) (Get-AdGroupMember $GroupB -Recursive | 
		Select -ExpandProperty SamAccountName) | %{
	If ($_.SideIndicator -eq "=>"){
	 $_ | Select @{N="User";E={$_.InputObject}},@{N="MissingIN";E={$GroupA}}
	 }Else{
	 $_ | Select @{N="User";E={$_.InputObject}},@{N="MissingIN";E={$GroupB}}
	 }
 }
}
Check-GroupDiff HelpdeskAdminGroup DesktopAdminGroup

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LVL 2

Author Comment

by:MilesLogan
ID: 41800811
hi Subsun , thats an awesome function but... what I was hoping to do is just get the total number of users.

If GroupA has 10 users and groupB has 4 users , I need it to show the difference .

so basically for it to output , "6 users missing from groupB "

can you help with this ?
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LVL 40

Accepted Solution

by:
Subsun earned 2000 total points
ID: 41801019
Try..
Function Check-GroupDiff ($GroupA,$GroupB){
$Comp = Compare (Get-AdGroupMember $GroupA -Recursive | 
Select -ExpandProperty SamAccountName) (Get-AdGroupMember $GroupB -Recursive | 
		Select -ExpandProperty SamAccountName)
	"$(($Comp | ?{$_.SideIndicator -eq "=>"} | Measure).Count) Users Missing in $GroupA"
	"$(($Comp | ?{$_.SideIndicator -eq "<="} | Measure).Count) Users Missing in $GroupB"
}
Check-GroupDiff HelpdeskAdminGroup DesktopAdminGroup

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Creating Active Directory Users from a Text File

If your organization has a need to mass-create AD user accounts, watch this video to see how its done without the need for scripting or other unnecessary complexities.

 
LVL 2

Author Comment

by:MilesLogan
ID: 41801788
Very cool ! thank you Subsun
0
 
LVL 2

Author Comment

by:MilesLogan
ID: 41801791
..
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LVL 2

Author Closing Comment

by:MilesLogan
ID: 41801792
thank you so much!
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