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UPLOAD FILE TO Web API USING POST

Posted on 2016-09-16
5
107 Views
Last Modified: 2016-09-19
I need to upload a file to a WebAPI, I'm using this code to do the upload

public void SendFilePost()
{  
    WebRequest request = WebRequest.Create(url);
    request.Method = "POST";
    byte[] byteArray = File.ReadAllBytes(fileName);
    request.ContentType = "multipart/form-data";
    request.ContentLength = byteArray.Length;

    Stream dataStream = request.GetRequestStream();
    dataStream.Write(byteArray, 0, byteArray.Length);
    dataStream.Close();
    WebResponse response = request.GetResponse();
    Console.WriteLine(((HttpWebResponse)response).StatusDescription);
    reader.Close();
    dataStream.Close();
    response.Close();
}
 In the WebAPI I have this code:

public async Task<HttpResponseMessage> Post()
    {
        if (!Request.Content.IsMimeMultipartContent("form-data"))
            return new HttpResponseException(HttpStatusCode.UnsupportedMediaType);

        var streamProvider =
            new MultipartFormDataStreamProvider(".");

        await Request.Content.ReadAsMultipartAsync(streamProvider);

        var fileNames = streamProvider.BodyPartFileNames;

        foreach (var fileName in fileNames.Keys)
            Console.WriteLine(fileName + " --> " + fileNames[fileName]);

        return new HttpResponseMessage(HttpStatusCode.Created);
    }

I'm always receiving this code:

HttpStatusCode.UnsupportedMediaType
0
Comment
Question by:Anderson Meneses
  • 2
  • 2
5 Comments
 
LVL 25

Expert Comment

by:dgrafx
ID: 41802526
You could use plupload
http://www.plupload.com/
0
 

Author Comment

by:Anderson Meneses
ID: 41802932
It's a good plugin, I will use it in my web projects, but this project is Winforms.
0
 
LVL 25

Expert Comment

by:dgrafx
ID: 41803040
I see ...

I'm not aware that you can't use plupload with winforms
0
 
LVL 29

Accepted Solution

by:
Gautham Janardhan earned 500 total points
ID: 41805154
try this to post

public static async void SendFilePost(string url, string fileName)
        {
            using (var client = new HttpClient())
            using (var content = new MultipartFormDataContent())
            {
                client.BaseAddress = new Uri(url);
                var fileContent1 = new ByteArrayContent(File.ReadAllBytes(fileName));
                fileContent1.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
                {
                    FileName = "mydata.txt"
                };
                content.Add(fileContent1, "mydata.txt");

// make sure to change this to ur api 

                var result = client.PostAsync("/api/home", content).Result;

                Console.WriteLine(result.StatusCode);
                Console.ReadLine();
            }
        }

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1
 

Author Closing Comment

by:Anderson Meneses
ID: 41805319
Very good. It worked fine!!!
0

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