?
Solved

How do I get multiple column values from data table.

Posted on 2016-09-21
4
Medium Priority
?
75 Views
Last Modified: 2016-09-21
Hi guys,

I have Person table and
dt has this table values.

 DataTable dt = getPersonTable();

Person table
I want to have FirstName and LastName for PersonId = 4 from DataTable, dt.

How can I accomplish this?
0
Comment
Question by:Isabell
4 Comments
 
LVL 45

Expert Comment

by:AndyAinscow
ID: 41808406
see https://msdn.microsoft.com/en-us/library/system.data.datatable.rows(v=vs.110).aspx

something like
PersonID = dt.Rows(0).Columns(0)
LastName = dt.Rows(0).Columns(1)
....
0
 
LVL 56

Assisted Solution

by:Ryan Chong
Ryan Chong earned 400 total points
ID: 41808413
you can also try:

DataRow[] dr = dt.Select("PersonId = '4' ")

Open in new window


then refer to DataRow collection instead.
0
 
LVL 10

Accepted Solution

by:
Paweł earned 1600 total points
ID: 41808418
you can also use linq

using System;
using System.Collections.Generic;
using System.Data;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication4
{
    class Program
    {
        static DataTable dt = new DataTable();
        static void Main(string[] args)
        {
            dt.Columns.Add(new DataColumn("Id", typeof(int)));
            dt.Columns.Add(new DataColumn("LastName", typeof(string)));
            dt.Columns.Add(new DataColumn("FirstName", typeof(string)));
            dt.Columns.Add(new DataColumn("BirthDate", typeof(DateTime)));

            NewRow(1, "paul", "chooch", new DateTime(1984, 1, 31));
            NewRow(2, "tom", "chooch", new DateTime(1988, 8, 28));
            NewRow(3, "john", "smith", new DateTime(1963, 7, 14));
            NewRow(4, "jane", "doe", new DateTime(1992, 4, 13));

            var output = dt.AsEnumerable()
                .Where(dr => dr.Field<int>("Id") == 2)
                .Select(dr => new
                {
                    fName = dr.Field<string>("FirstName"),
                    lName = dr.Field<string>("LastName")
                  
                    
                }).FirstOrDefault();

            Console.WriteLine( output.fName + " " + output.lName);

        // or combine mine and Ryan's approach
        var output2 = dt.Select("Id = 2")
                .Select(dr => dr.Field<string>("FirstName") + " " + dr.Field<string>("LastName") ).First();

            Console.WriteLine(output2);
        }

        static void NewRow(int id, string lName, string fName, DateTime bDate)
        {
            var dr = dt.NewRow();
            dr.SetField("Id", id);
            dr.SetField("LastName", lName);
            dr.SetField("FirstName", fName);
            dr.SetField("BirthDate", bDate);
            dt.Rows.Add(dr);
        }
    }
}

Open in new window

0
 
LVL 44

Expert Comment

by:zephyr_hex (Megan)
ID: 41809056
Here is how I would approach it:
//select record(s) to data rows
DataRow[] childRow = dt.Select("PersonId = 4");
//if at least one record is found
if(childRow.Any())
{
    //copy rows to a datatable
    DataTable childDt = childRows.CopyToDataTable();
}

Open in new window



or, if you just want the First and Last name, you can do:

var test = from row in dt.AsEnumerable()
                    where row.Field<int>("PersonId") == 4
                    select new {First = row.Field<string>("FirstName"), Last = row.Field<string>("LastName")};

Open in new window

0

Featured Post

Keep up with what's happening at Experts Exchange!

Sign up to receive Decoded, a new monthly digest with product updates, feature release info, continuing education opportunities, and more.

Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

Join & Write a Comment

This article aims to explain the working of CircularLogArchiver. This tool was designed to solve the buildup of log file in cases where systems do not support circular logging or where circular logging is not enabled
This article describes and provides a custom-made tool I wrote to give businesses a means of identifying commercial music content, without having to expend too much effort. Business recordings are easily identified from possibly illegal music files …
Hi, this video explains a free download that you can incorporate into your Access databases, or use stand-alone for contact management. Contacts -- Names, Addresses, Phone Numbers, eMail Addresses, Websites, Lists, Projects, Notes, Attachments…
To export Lotus Notes to Outlook PST or Exchange and Domino Server files to Exchange Server or PST files with ease, go for Kernel for Lotus Notes to Outlook conversion tool. Through the video, you can watch the conversion process. A common user with…

590 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question