Solved

pairstar challenge

Posted on 2016-09-21
2
78 Views
Last Modified: 2016-09-22
Hi,

I am working on below challenge.
http://codingbat.com/prob/p158175
Psedo code:
1. check the array length 0  or 1 then retun same str
2.else return string with * in between for repeated pair of characters

I wrote my code as below and not passing all tests
public String pairStar(String str) {
  
  if(str.length()==0||str.length()==1){
    return str;
  }
  else{
  return str.charAt(0)+"*"+pairStar(str.substring(1));
  }

}

Open in new window


Expected      Run            
pairStar("hello") → "hel*lo"      "h*e*l*l*o"      X      
pairStar("xxyy") → "x*xy*y"      "x*x*y*y"      X      
pairStar("aaaa") → "a*a*a*a"      "a*a*a*a"      OK      
pairStar("aaab") → "a*a*ab"      "a*a*a*b"      X      
pairStar("aa") → "a*a"      "a*a"      OK      
pairStar("a") → "a"      "a"      OK      
pairStar("") → ""      ""      OK      
pairStar("noadjacent") → "noadjacent"      "n*o*a*d*j*a*c*e*n*t"      X      
pairStar("abba") → "ab*ba"      "a*b*b*a"      X      
pairStar("abbba") → "ab*b*ba"      "a*b*b*b*a"      X      
other tests

Any improvements or alternate approaches?      

please advise
0
Comment
Question by:gudii9
[X]
Welcome to Experts Exchange

Add your voice to the tech community where 5M+ people just like you are talking about what matters.

  • Help others & share knowledge
  • Earn cash & points
  • Learn & ask questions
2 Comments
 
LVL 7

Author Comment

by:gudii9
ID: 41809272
public String pairStar(String str) {
  
  if(str.length()==0||str.length()==1){
    return str;
  }
  else if(str.charAt(0)==str.charAt(1)){
  return str.charAt(0)+"*"+pairStar(str.substring(1));
  }
 else{
  return str.charAt(0)+pairStar(str.substring(1));
  }
}

Open in new window


above passed all tests. any improvements or alternate approaches?
0
 
LVL 27

Accepted Solution

by:
rrz earned 500 total points
ID: 41809535
Your code is good. Personally, I would clean it up a little.
public String pairStar(String str) {
  if(str.length() < 2){
    return str;
  }
  if(str.charAt(0) == str.charAt(1)){
    return str.charAt(0) + "*" + pairStar(str.substring(1));
  }
  return str.charAt(0) + pairStar(str.substring(1));
}

Open in new window

0

Featured Post

Salesforce Made Easy to Use

On-screen guidance at the moment of need enables you & your employees to focus on the core, you can now boost your adoption rates swiftly and simply with one easy tool.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

Suggested Solutions

Title # Comments Views Activity
java imports not found 4 71
Java 8 to Java 6 8 43
spring maven example issues 3 106
How to retrieve the HTTPServletResponse header field in script tag 1 43
I had a project requirement for a displaying a user workbench .This workbench would consist multiple data grids .In each grid the user will be able to see a large number of data. These data grids should allow the user to 1. Sort 2. Export the …
Java functions are among the best things for programmers to work with as Java sites can be very easy to read and prepare. Java especially simplifies many processes in the coding industry as it helps integrate many forms of technology and different d…
Viewers will learn about if statements in Java and their use The if statement: The condition required to create an if statement: Variations of if statements: An example using if statements:
This tutorial covers a step-by-step guide to install VisualVM launcher in eclipse.
Suggested Courses

751 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question