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Python 2.7 - Passing arguments

Hi there,

From the windows shell, I need to start my project by passing an argument to it.

Command line: task.py "These are strings" "9"
Where 9 is a number

print "argument1"
type (argument1)
print("") #CLRF is intended here

print argument2 + 100
type (argument2)

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Thanks for your help,
Rene

gelonida

what you are looking foir is sys.argv, which works for windows and other OSes

import sys
args = sys.argv[1:]
if len(args) < 2:
    print("ERROR: at least 2 arguments required, but got only %d"  % len(args))
    sys.exit(1)

argument1, argument2  = args[:2]
argument2 = int(argument2)

print("argument1 %r" % argument1)
print("") #CLRF is intended here

print(int(argument2) + 100)

Open in new window

you might also look at a much more complex but very flexible solution for parsing command line arguments.

the module is called https://docs.python.org/3/library/argparse.html
it is used to parse / validate sys.argv[1:]

ReneGe

ASKER

Hi Gelonida,

Thanks for your prompt response :)

Here is the output I got:
ERROR: at least 2 arguments required, but got only 0

My command line was: task.py "qq" "9"

Cheers

ASKER CERTIFIED SOLUTION

gelonida

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ReneGe

ASKER

Yea it's working

I omitted to add python in my command line :)

I'll know better next time!

Thanks for your help
Cheers

ReneGe

ASKER

Here is my followup question:
https://www.experts-exchange.com/questions/28971470/Python-2-7-Save-to-file.html

Cheers

gelonida

Good to know that you got it working.

However on my Windows machine I'm not obliged to type python before the command.

I guess, that your python launcher is not configured as it should be.

ReneGe

ASKER

Maybe I should associate .py extensions to my python.exe

ReneGe

ASKER

Did not work! Oh well, I guess I can create a new question for this one as well
Thanks :)