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nestparen challenge

Posted on 2016-09-21
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Last Modified: 2016-09-22
Hi,

I am working on below challenge

http://codingbat.com/prob/p183174
Recursion-1 > nestParen
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Given a string, return true if it is a nesting of zero or more pairs of parenthesis, like "(())" or "((()))". Suggestion: check the first and last chars, and then recur on what's inside them.

nestParen("(())") → true
nestParen("((()))") → true
nestParen("(((x))") → false

i was not clear on description. please advies
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Question by:gudii9
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4 Comments
 
LVL 37

Accepted Solution

by:
zzynx earned 500 total points
ID: 41810247
You have to check if each opening bracket '(' in the string has a corresponding closing bracket ')'
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LVL 7

Author Comment

by:gudii9
ID: 41810913
i understood now. let me think
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LVL 7

Author Comment

by:gudii9
ID: 41811215
public boolean nestParen(String str) {

if(str.equals("")){
  return true;
}
else if( str.charAt(0)=='(' && str.charAt(str.length()-1) ==')'  ){
  
  return nestParen(str.substring(1,str.length()-1));
}
else{
  return false;
}
}

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above passes ll tests. any improvements or alternate approaches?
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LVL 37

Expert Comment

by:zzynx
ID: 41811978
Not really.

public boolean nestParen(String str) {
   if(str.length()==0){
     return true;
   }
   if( str.charAt(0)=='(' && str.charAt(str.length()-1) ==')' ){
     return nestParen(str.substring(1,str.length()-1));
   }
   return false;
}

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