nestparen challenge

Hi,

I am working on below challenge

http://codingbat.com/prob/p183174
Recursion-1 > nestParen
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Given a string, return true if it is a nesting of zero or more pairs of parenthesis, like "(())" or "((()))". Suggestion: check the first and last chars, and then recur on what's inside them.

nestParen("(())") → true
nestParen("((()))") → true
nestParen("(((x))") → false

i was not clear on description. please advies
LVL 7
gudii9Asked:
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zzynxSr. Software engineerCommented:
You have to check if each opening bracket '(' in the string has a corresponding closing bracket ')'

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gudii9Author Commented:
i understood now. let me think
gudii9Author Commented: 
public boolean nestParen(String str) {

if(str.equals("")){
  return true;
}
else if( str.charAt(0)=='(' && str.charAt(str.length()-1) ==')'  ){
  
  return nestParen(str.substring(1,str.length()-1));
}
else{
  return false;
}
}

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above passes ll tests. any improvements or alternate approaches?
zzynxSr. Software engineerCommented:
Not really.

public boolean nestParen(String str) {
   if(str.length()==0){
     return true;
   }
   if( str.charAt(0)=='(' && str.charAt(str.length()-1) ==')' ){
     return nestParen(str.substring(1,str.length()-1));
   }
   return false;
}

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