Link to home
Start Free TrialLog in
Avatar of lawrence_dev

asked on

Need assistance with join statement PHP/PDO

How do I correctly structure this join statement?

$query1 = $conn->query("SELECT * FROM `Outdoor_Invoices` LEFT JOIN `oc_order` USING (order_id) WHERE PONo = 'order_id'");

//LEFT JOIN `oc_url_alias` USING (query) WHERE product_id');

    while ($row1 = $query1->fetch(PDO::FETCH_ASSOC))
	$orderid = $row1['order_id'];
	$InvAmt = $row1['InvAmt'];
	$OrderTotal = $row1['total'];
	$Profit = ($total - $InvAmt);
$conn->query("UPDATE `Outdoor_Invoices` SET OrderTotal = $OrderTotal, Profit = $Profit WHERE PONo = '$orderid'");

Open in new window

Avatar of Terry Woods
Terry Woods
Flag of New Zealand image

Which one?
Avatar of lawrence_dev


Thanks Terry!  I tried a little variation and still cannot get it to work.

$query1 = $conn->query("SELECT * FROM `Outdoor_Invoices` LEFT JOIN `oc_order` USING (order_id) WHERE Outdoor_Invoices.PONo = oc_order.'order_id'");
I wonder if it's because order_id is in single quotes rather than backticks? You don't need them anyway for the given table and column names.

Try this:
$query1 = $conn->query("
SELECT * FROM Outdoor_Invoices
LEFT JOIN oc_order USING (order_id) 
WHERE Outdoor_Invoices.PONo = oc_order.order_id

Open in new window

Terry,  the columns and table names are correct, however, I am getting the following error:

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42S22]: Column not found: 1054 Unknown column 'order_id' in 'from clause'' in OutdoorProfit.php:125 Stack trace: #0 OutdoorProfit.php(125): PDO->query('SELECT * FROM O...') #1 {main} thrown in OutdoorProfit.php on line 125

Column  /   Table

PONo   /  Outdoor_Invoices

order_id  /  oc_order
Avatar of Terry Woods
Terry Woods
Flag of New Zealand image

Link to home
This solution is only available to members.
To access this solution, you must be a member of Experts Exchange.
Start Free Trial
Sorry Terry for the delay!!  That worked great!!  THANKS!!!