Sign up to receive Decoded, a new monthly digest with product updates, feature release info, continuing education opportunities, and more.
My first post was an observation rather than a proof.
All three LHS terms in the first equation are quadratics in x.
Evaluate both LHS expressions at x = a, x = b, x = c
In each case, two of the quotients go to zero and the third to one.
In each case, two of the quotients go to zero and the third to one.In the first equation, two of the terms (which are the coefficients of a, b, and c in the second) go to zero and the third to one.
Not true.
Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.
Have a better answer? Share it in a comment.
Rearrange the terms. Expand the sub-terms. Use a common denominator to get one fraction. Multiply by that denomiator and reduce the terms by using the balance method. In the end you should get 1=1 or 0=0 as result.