AD security group memberships changes

would there be any default logs or techniques (e.g. powershell commands), to identify when a user was added to the membership of an AD security group - and the date the user was added? We need to pick a sample of users who have recently been granted access to existing security groups to ensure it was properly authorised.
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pma111Asked:
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yo_beeDirector of Information TechnologyCommented:
In Group Policy there are options to enable Directory Services
Here is a link how to set it up.
https://technet.microsoft.com/en-us/library/dd277403.aspx
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Subash SundharanIT Infrastructure Architect Commented:
If you have already enabled active directory auditing then you can look in event logs on domain controllers, to find the events. Else it's not possible. If you enable the Auditing, the logs can capture events from when it's enabled.
Ref :
Audit Security Group Management
  https://technet.microsoft.com/en-us/library/dd772663(v=ws.10).aspx
AD DS Auditing Step-by-Step Guide
  https://technet.microsoft.com/en-us/library/cc731607(v=ws.10).aspx
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pma111Author Commented:
Hi subsun - where can you check if AD auditing has been enabled or not - and where by default would these logs reside?
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Subash SundharanIT Infrastructure Architect Commented:
In the Default Domain Controller Policy,  
Computer Configuration > Windows Settings > Security Settings > Local Policies > Audit Policy
Check Audit Directory Services Access, Audit Account Management etc..

If the auditing is not enabled then you will see 'No Auditing', If it's enabled then you can see 'Success, Failure'

You can open the Security Log to view logged events.
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pma111Author Commented:
thanks.

By security log, do you just mean the default windows security log, i.e.

%SystemRoot%\System32\Winevt\Logs\Security.evtx
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Subash SundharanIT Infrastructure Architect Commented:
Yes.. you can access, eventvwr > Windows Logs > Security
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Subash SundharanIT Infrastructure Architect Commented:
Expert comments have answered the queries. The question can be closed if @pma111 doesn't have any objections.
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