Modifying Powershell script to get the size of the directory ?

Hi,

Can anyone assist in modifying the below script so that it can also list the directory size ?
by combining this script from: https://technet.microsoft.com/en-us/library/ff730945.aspx

and this one to list Home folder from disabled user accounts.

$subFolderItems = (Get-ChildItem $i.FullName | Measure-Object -property length -sum)
$i.FullName + " -- " + "{0:N2}" -f ($subFolderItems.sum / 1MB) + " MB"

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Get-ADUser -SearchBase "OU=Disabled USERS,OU=Main Office,DC=domain,DC=com" -F * -Pr HomeDirectory | ?{$_.HomeDirectory} | Select Name,HomeDirectory | Export-CSV C:\report.csv -nti

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Get-ADUser -SearchBase "OU=Disabled USERS,OU=Main Office,DC=domain,DC=com" -F * -Pr HomeDirectory | ?{$_.HomeDirectory -match "^\\\\FileServerHQ\\Users"} | Select Name,HomeDirectory | Export-CSV C:\report.csv -nti

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This is a continuation from this thread: https://www.experts-exchange.com/questions/28972587/Modifying-PowerShell-to-list-home-drives-of-disabled-users.html#a41817693

Thanks in advance.
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Senior IT System EngineerIT ProfessionalAsked:
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SubsunConnect With a Mentor Commented:
Change
Select Name,HomeDirectory

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to
Select Name,HomeDirectory,@{N="Size";E={"{0:N2}" -f ((Get-ChildItem $_.HomeDirectory -Recurse | Measure-Object -property length -sum).sum / 1MB) + " MB"}}

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Senior IT System EngineerIT ProfessionalAuthor Commented:
Thanks it works !
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