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mapBully challenge

Posted on 2016-09-27
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Last Modified: 2016-09-30
Hi,

 I am working on below challenge
http://codingbat.com/prob/p197888


[/Map-1 > mapBully
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Modify and return the given map as follows: if the key "a" has a value, set the key "b" to have that value, and set the key "a" to have the value "". Basically "b" is a bully, taking the value and replacing it with the empty string.

mapBully({"b": "dirt", "a": "candy"}) → {"b": "candy", "a": ""}
mapBully({"a": "candy"}) → {"b": "candy", "a": ""}
mapBully({"b": "carrot", "c": "meh", "a": "candy"}) → {"b": "candy", "c": "meh", "a": ""}

how below got below result

mapBully({"a": "candy"}) → {"b": "candy", "a": ""}

there is no b in the input map right then how it came in the output map?
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Question by:gudii9
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6 Comments
 
LVL 37

Accepted Solution

by:
zzynx earned 250 total points
ID: 41819221
>> there is no b in the input map right then how it came in the output map?

It exactly does what is required:
Modify and return the given map as follows:
1) if the key "a" has a value, set the key "b" to have that value,
   {"a": "candy"}  == becomes ==> {"a": "candy", "b": "candy"}
2) and set the key "a" to have the value ""
   {"a": "candy", "b": "candy"}  == becomes ==> {"a": "", "b": "candy"}
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LVL 36

Assisted Solution

by:mccarl
mccarl earned 250 total points
ID: 41821042
there is no b in the input map right then how it came in the output map?

Because your code will add the "b" to the map
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LVL 7

Author Comment

by:gudii9
ID: 41822175
public Map<String, String> mapBully(Map<String, String> map) {
  String val=map.get("a");
  String backup=val;
  map.put("b",backup);
  map.put("a","");
  
  return map;
}

Open in new window


failing two tests.
Expected      Run            
mapBully({"b": "dirt", "a": "candy"}) → {"b": "candy", "a": ""}      {"b": "candy", "a": ""}      OK      
mapBully({"a": "candy"}) → {"b": "candy", "a": ""}      {"b": "candy", "a": ""}      OK      
mapBully({"b": "carrot", "c": "meh", "a": "candy"}) → {"b": "candy", "c": "meh", "a": ""}      {"b": "candy", "c": "meh", "a": ""}      OK      
mapBully({"b": "carrot"}) → {"b": "carrot"}      {"b": null, "a": ""}      X      
mapBully({"c": "meh"}) → {"c": "meh"}      {"b": null, "c": "meh", "a": ""}      X      
mapBully({"c": "meh", "a": "sparkle"}) → {"b": "sparkle", "c": "meh", "a": ""}      {"b": "sparkle", "c": "meh", "a": ""}      OK      
please advise
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LVL 7

Author Comment

by:gudii9
ID: 41822192
public Map<String, String> mapBully(Map<String, String> map) {
  if(map.containsKey("a")){
  String val=map.get("a");
  String backup=val;
  map.put("b",backup);
  map.put("a","");
  }
  return map;
}

Open in new window

above passes all tests. any improvements or alternate approaches?
0
 
LVL 37

Expert Comment

by:zzynx
ID: 41823011
>> any improvements
Yes.
1. Indent your code decently
2. There's no need to work with those temporary variables

public Map<String, String> mapBully(Map<String, String> map) {
    if (map.containsKey("a")) {
       map.put("b", map.get("a"));
       map.put("a","");
    }
    return map;
}

Open in new window

0
 
LVL 12

Expert Comment

by:tel2
ID: 41823016
And you could have seen the code in the above post if you'd simply clicked the "Show Solution" button next to the "Go" button on the codingbat webpage you linked to.
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