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word0 challenge

Posted on 2016-09-29
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Last Modified: 2016-09-30
Hi,

I am working on below challenge.
http://codingbat.com/prob/p152303

public Map<String, Integer> word0(String[] strings) {
  int len=strings.length;
   Map<String, Integer> map = new HashMap<String, Integer>();
 for(int i=0;i<len;i++){
   
 map.put(strings[i],0);
 }
  return map;
}

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i passed all tests. any improvements or alternate approaches? please advise
0
Comment
Question by:gudii9
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4 Comments
 
LVL 33

Accepted Solution

by:
ste5an earned 250 total points
ID: 41823210
No need for an extra variable:

public Map<String, Integer> word0(String[] strings) {
  Map<String, Integer> result = new HashMap<String, Integer>();
  for (int count = 0; count < strings.length; count++) 
  {
      result.put(strings[count], 0);
  }
  
  return result;
}

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0
 
LVL 37

Assisted Solution

by:zzynx
zzynx earned 250 total points
ID: 41823211
Pretty straightforward.
No real improvements.
You could write your loop also as

for (String s : strings) {
    map.put(s, 0);
}

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0
 
LVL 37

Expert Comment

by:zzynx
ID: 41823213
>> No need for an extra variable
I don't know.
Without that variable, for each iteration of the loop you'll evaluate
strings.length
If you store that value in a variable, you only determine the length once.

(But I guess compiler optimalisation will do that for you)
0
 
LVL 33

Expert Comment

by:ste5an
ID: 41823217
(But I guess compiler optimalisation will do that for you)

Yup, in both cases.
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