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maqskywalker

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placing image in table cell with jquery

Hi experts,

This is my code so far
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
    <title></title>
  
    <script type="text/javascript" src="http://code.jquery.com/jquery-1.9.1.js"></script>

    <style type="text/css">
        #Table1 {
            width: 800px;
        }

        #row1 {
            height: 50px;
        }
        #row2 {
            height: 50px;
        }
        #row3 {
            height: 50px;
        }
        #row4 {
            height: 50px;
        }
        .col1 {
            width: 200px;
            font-family: Arial;
            font-weight: bold;
            font-size: 12px;
            border: 1px solid #b200ff;
            vertical-align: top;
        }
        .col2 {
            width: 200px;
            font-family: Arial;
            font-weight: bold;
            font-size: 12px;
            color: #006600;
            border: 1px solid #006600;
            vertical-align: top;
        }
        .col3 {
            width: 200px;
            font-family: Arial;
            font-weight: bold;
            font-size: 12px;
            color: #006600;
            border: 1px solid #123eeb;
        }
        .col4 {
            width: 200px;
            font-family: Arial;
            font-weight: bold;
            font-size: 12px;
            color: #006600;
            border: 1px solid #0094ff;
        }
    </style>

    <script type="text/javascript">
        $(document).ready(function () {
            // -------------------
                                        

            // ---- On Page Load ---- 

            // http://stackoverflow.com/questions/28552516/append-image-to-td-via-jquery
            
            var img = document.createElement("img");
            img.src = "http://media.idownloadblog.com/wp-content/uploads/2014/12/Google-Drive-3.4-for-iOS-app-icon-small.png";

            $('#Table1').find(tbody).append("<td>" + img + "</td>");

            
            // ---- On Page Load ---- 
            

            // -------------------
        });
    </script>

</head>
<body>

        <div>
            <table id="Table1">
                <tr id="row1">                    
                    <td class="col1"></td>
                    <td class="col2"></td>        
                    <td class="col3"></td>  
                    <td class="col4"></td>      
                </tr>
                <tr id="row2">                    
                    <td class="col1"></td>
                    <td class="col2"></td>        
                    <td class="col3"></td>  
                    <td class="col4"></td>                                                      
                </tr>
                <tr id="row3">                    
                    <td class="col1"></td>
                    <td class="col2"></td>        
                    <td class="col3"></td>  
                    <td class="col4"></td>                                                      
                </tr>
                <tr id="row4">                    
                    <td class="col1"></td>
                    <td class="col2"></td>        
                    <td class="col3"></td>  
                    <td class="col4"></td>                                                      
                </tr>
            </table>
            <br />

        </div>

</body>
</html>

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My code is incorrect. Its not working.

What i want is....
Using jQuery, On page load, place the image inside col4 of row1 of the table with id of Table1

Anyone know the syntax for that?
ASKER CERTIFIED SOLUTION
Avatar of Amita Singh
Amita Singh
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SOLUTION
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Julian Hansen
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Alternative - last-child instead of nth-child
$(function() {
  var img = $('<img/>', {
    src: "http://media.idownloadblog.com/wp-content/uploads/2014/12/Google-Drive-3.4-for-iOS-app-icon-small.png"
  });
  // Independent of ID's and classes
  $('#Table1 tr:first-child td:last-child').append(img);
});

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Avatar of maqskywalker
maqskywalker

ASKER

thanks. both are great solutions.
You are welcome.