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SQL Insert Query Help, part2

This is related to the schema/sample data already posted on this question:
here


I have 2 rows that need to be added to a table, `wp_posts` that have a count for the number of contacts for a given post_id.   One row will have a meta_key of 'contacts' and the meta_value will be the count.  The 2nd row meta_key will be '_contacts' and meta_value will always be 'field_5790aaada7333'.  The post_id will be the same for both rows.  So for example, using the sample data posted on the other question, the rows would look like this when finished:
post_id 	meta_key 	meta_value
3001 	contacts 	5
3001 	_contacts 	field_5790aaada7333
3003 	contacts 	1
3003 	_contacts 	field_5790aaada7333
3005 	contacts 	2
3005 	_contacts 	field_5790aaada7333
3008 	contacts 	4
3008 	_contacts 	field_5790aaada7333

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The other issue with this is that the rows may exist for a given already, and if so only the first row need to be updated with the actual number of contacts.  My thought was to count the number of rows where the meta_key is like one of the meta_keys that is static, i.e. field_5790aac3a7334, for a given post_id, however I am unsure of how to either update the value of a row or insert 2 new rows if the rows do not exist.
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bdhtechnology
Asked:
bdhtechnology
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1 Solution
 
bdhtechnologyAuthor Commented:
Actually there are only 7 rows where the fields exist already, so the part regarding the update portion of the query can be ignored, I just need to add 2 rows for each post_id to count the number of contacts.
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PortletPaulfreelancerCommented:
can this be a separate query?

I am about to finish up for the night, so thi s is as far as my sleepy eyes would let me go.. hope it helps

SELECT
...
  CASE
         WHEN cj.n = 1 THEN c.contact_count
         WHEN cj.n = 2 THEN 'field_5790aaada7333'
  END AS meta_value
FROM (
    SELECT
         cc.company
       , COUNT(*) contact_count
    FROM `chambercontacts` cc
    GROUP BY
         cc.company
      ) c
...
CROSS JOIN (
          SELECT 1 n UNION ALL
          SELECT 2 n
         ) cj
    

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bdhtechnologyAuthor Commented:
Yes, I have the rows inserted now but to use them I need to have the correct count for the actual number of contacts.
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PortletPaulfreelancerCommented:
please refresh page, my lat comment was being changed as you added :)

I'm off to bed I'm afraid way too tired
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bdhtechnologyAuthor Commented:
That was quite helpful, with a few tweaks I was able to finish this up.  Thanks for all of your help!

INSERT INTO `wp_postmeta` (`post_id`, `meta_key`, `meta_value`)
SELECT
  p.ID AS post_id,
  CASE
         WHEN cj.n = 1 THEN 'contacts'
         WHEN cj.n = 2 THEN '_contacts'
  END AS meta_key,
  CASE
         WHEN cj.n = 1 THEN c.contact_count
         WHEN cj.n = 2 THEN 'field_5790aaada7333'
  END AS meta_value
FROM (
  SELECT
     cc.company,
     cc.deleted,
     COUNT(*) contact_count
  FROM `chambercontacts` cc
  WHERE cc.deleted=0
  GROUP BY
       cc.company
  ) c
  LEFT JOIN `directory` d ON c.company=d.id
  LEFT JOIN `wp_posts` p ON d.companyname LIKE p.post_title
  CROSS JOIN (
          SELECT 1 n UNION ALL
          SELECT 2 n
  ) cj
WHERE
  d.deleted=0 AND
  p.ID>=3000;

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PortletPaulfreelancerCommented:
Great! Thanks for the question(s). Cheers, Paul
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