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Remove leading, trailing space and leading zeros from string

Hi guys,

I'm using 'parseInt' function to
// Removes all leading and trailing white-space characters from the string and then
// Removes all leading occurrences of the specified character 0 (zeros)

var invoiceId = parseInt(document.getElementById("txtId").value) || "";

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input: invoiceId = " 0001abc2345 ";
output result: invoiceId ="1" // 'parseInt' function removes all alpha charters
output required: invoiceId ="1abc2345"

Any other way to remove leading and trailing white-space and leading zeros?

Darius

ASKER

If no solution on this will try to user Regex....

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Julian Hansen

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SOLUTION

Julian Hansen

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Darius

ASKER

Julian,

it works for :
var src = '00001abacd45';
result: '1abacd45'

This one gives incorrect result:
var src = '00001aba$_cd45';
result: '1aba'

Acceptation for alphanumeric with one additional character (hyphen)

Julian Hansen

You need to let us know what the data requirements are - your original example did not have an underscore
just change the pattern to /0+([\w_]+)/

	var result = src.match(/0+([\w_]+)/);

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Julian Hansen

Belay that the original was fine as it was. Underscore is included in the \w match.

var src = '   00001abac_d45  ';
var result = src.match(/0+(\w+)/);
console.log(result);

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Working sample here

Darius

ASKER

Thank you! Working!!!

Now I thinking another situation:
How to remove leading trailing white-space and leading zeros only. Other numbers, alphabetic characters and any possible characters to leave as it is.

var src = '   001abc!"$%^&*()_+234  ';
// result:  '1abc!"$%^&*()_+234

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'

Thank you!

Darius

ASKER

var src = '   001abc!"$%^&*()_+234  ';

// result:  '1abc!"$%^&*()_+234'

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SOLUTION

Julian Hansen

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Darius

ASKER

Thanks again...

I tried something similar. I did mistake by using trim() function...

Julian Hansen

You are welcome.