asked on Remove leading, trailing space and leading zeros from string
Hi guys,
I'm using 'parseInt' function to
// Removes all leading and trailing white-space characters from the string and then
// Removes all leading occurrences of the specified character 0 (zeros)
output result: invoiceId ="1" // 'parseInt' function removes all alpha charters
output required: invoiceId ="1abc2345"
Any other way to remove leading and trailing white-space and leading zeros?
I'm using 'parseInt' function to
// Removes all leading and trailing white-space characters from the string and then
// Removes all leading occurrences of the specified character 0 (zeros)
var invoiceId = parseInt(document.getElementById("txtId").value) || "";
output result: invoiceId ="1" // 'parseInt' function removes all alpha charters
output required: invoiceId ="1abc2345"
Any other way to remove leading and trailing white-space and leading zeros?
JavaScript
Last Comment
Julian Hansen
ASKER
If no solution on this will try to user Regex....
ASKER CERTIFIED SOLUTION
THIS SOLUTION ONLY AVAILABLE TO MEMBERS.
View this solution by signing up for a free trial.
Members can start a 7-Day free trial and enjoy unlimited access to the platform.
SOLUTION
THIS SOLUTION ONLY AVAILABLE TO MEMBERS.
View this solution by signing up for a free trial.
Members can start a 7-Day free trial and enjoy unlimited access to the platform.
ASKER
Julian,
it works for :
var src = '00001abacd45';
result: '1abacd45'
This one gives incorrect result:
var src = '00001aba$_cd45';
result: '1aba'
Acceptation for alphanumeric with one additional character (hyphen)
it works for :
var src = '00001abacd45';
result: '1abacd45'
This one gives incorrect result:
var src = '00001aba$_cd45';
result: '1aba'
Acceptation for alphanumeric with one additional character (hyphen)
You need to let us know what the data requirements are - your original example did not have an underscore
just change the pattern to /0+([\w_]+)/
just change the pattern to /0+([\w_]+)/
var result = src.match(/0+([\w_]+)/);
Belay that the original was fine as it was. Underscore is included in the \w match.
var src = ' 00001abac_d45 ';
var result = src.match(/0+(\w+)/);
console.log(result);
ASKER
Thank you! Working!!!
Now I thinking another situation:
How to remove leading trailing white-space and leading zeros only. Other numbers, alphabetic characters and any possible characters to leave as it is.
Thank you!
Now I thinking another situation:
How to remove leading trailing white-space and leading zeros only. Other numbers, alphabetic characters and any possible characters to leave as it is.
var src = ' 001abc!"$%^&*()_+234 ';
// result: '1abc!"$%^&*()_+234
Thank you!
ASKER
var src = ' 001abc!"$%^&*()_+234 ';
// result: '1abc!"$%^&*()_+234'
SOLUTION
THIS SOLUTION ONLY AVAILABLE TO MEMBERS.
View this solution by signing up for a free trial.
Members can start a 7-Day free trial and enjoy unlimited access to the platform.
ASKER
Thanks again...
I tried something similar. I did mistake by using trim() function...
I tried something similar. I did mistake by using trim() function...
You are welcome.