Need help error handling a windows service

Good morning Experts,
I need help error handling a windows service I wrote in VB.Net.

I put all of my processes in a Try \ Catch block.  When an error is encountered the code in the Catch executes and logs the error.
I want to prevent the service from stopping and to just continue to process the next record.  How can I do this?

thanks,
mrotor
mainrotorAsked:
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it_saigeConnect With a Mentor DeveloperCommented:
It depends on your logic...  You may put everything into a try...catch block but you need to understand what that means and how it can affect the flow of your logic.

For example, what is the difference between this:
Module Module1
	Sub Main()
		Console.WriteLine("Starting Service")
		RunService()
		Console.WriteLine("Exiting Service")
		Console.ReadLine()
	End Sub

	Sub RunService()
		Try
			While (True)
				Console.WriteLine("Processing...")
				Throw New Exception("Exception Thrown")
			End While
		Catch ex As Exception
			Console.WriteLine(ex.Message)
		End Try
	End Sub
End Module

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And this:
Module Module1
	Sub Main()
		Console.WriteLine("Starting Service")
		RunService()
		Console.WriteLine("Exiting Service")
		Console.ReadLine()
	End Sub

	Sub RunService()
		While (True)
			Try
				Console.WriteLine("Processing...")
				Throw New Exception("Exception Thrown")
			Catch ex As Exception
				Console.WriteLine(ex.Message)
			End Try
		End While
	End Sub
End Module

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The difference is the location of the exception.  The first code example will stop processing when the the first exception is thrown because the try...catch encloses the processing loop; e.g. -Capture.JPGWhereas, the second code example will continue to run into perpetuity; e.g. -Capture.JPG
So, again, it comes down to your logic and it's layout.

-saige-
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Snarf0001Commented:
It should already be doing that.  As long as you're not rethrowing in the catch block, then it won't stop the service.

If it is, you must have another failing block somewhere that's not wrapped in a try.
If you can post the code / error message, can see.
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