SQL for monthly balance change

Working with a table that has a data as shown below. How do I write a T-SQL statement that shows the monthly change in balance over 12 consecutive months? Thanks.

PERIOD      AVG_MTD_ACTL
201501      $19,833,568.74
201502      $20,545,226.37
201503      $20,207,922.27
201504      $20,275,581.84
201505      $20,220,454.21
201506      $20,213,055.00
201507      $20,232,099.51
201508      $20,250,648.82
201509      $20,248,825.95
201510      $20,224,476.03
201511      $19,905,864.93
201512      $20,503,382.87
saved4useAsked:
Who is Participating?
 
Pawan KumarConnect With a Mentor Database ExpertCommented:
Pls try this.. I

--

;WITH CTE AS
(
       SELECT * , CAST( (LEFT(PERIOD,4) +  RIGHT(PERIOD,2) + '01') AS DATE ) dt FROM tryqw
)
SELECT a.PERIOD , a.AVG_MTD_ACTL, a.AVG_MTD_ACTL - ISNULL(bn,a.AVG_MTD_ACTL) Differences FROM CTE a
OUTER APPLY
(
      SELECT TOP 1 b.AVG_MTD_ACTL bn
	  FROM CTE b      
	  WHERE a.dt > b.dt
	  ORDER BY b.dt DESC
)t


--

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1
 
Terry WoodsIT GuruCommented:
Do you mean a single dollar value that is the difference between a given month and a year before that?
0
 
Pawan KumarDatabase ExpertCommented:
Hi,

Pls try this... If you need something different , please provide output expected. Thanks

--

CREATE TABLE tryqw
(
	 PERIOD BIGINT
	,AVG_MTD_ACTL NUMERIC(25,2)
)
GO

INSERT INTO tryqw VALUES
(201501,      19833568.74),
(201502,      20545226.37),
(201503,      20207922.27),
(201504,      20275581.84),
(201505,      20220454.21),
(201506,      20213055.00),
(201507,      20232099.51),
(201508,      20250648.82),
(201509,      20248825.95),
(201510,      20224476.03),
(201511,      19905864.93),
(201512,      20503382.87)
GO

;WITH CTE AS
(
       SELECT * , DATEFROMPARTS( LEFT(PERIOD,4) ,  RIGHT(PERIOD,2) , '01' ) dt FROM tryqw
)
,CTE1 AS
(
       SELECT a.PERIOD , a.AVG_MTD_ACTL , ISNULL(qw.MonthySumChange,0) MonthySumChange FROM CTE a	  
       CROSS APPLY
       (
             SELECT SUM(b.AVG_MTD_ACTL) MonthySumChange 
             FROM CTE b
             WHERE b.dt BETWEEN DATEADD(M,-11,a.dt) AND DATEADD(M,-1,a.dt)
       )qw
	   
)
SELECT * FROM CTE1


--

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0
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Pawan KumarDatabase ExpertCommented:
Or may be you need this.

--




CREATE TABLE tryqw
(
	 PERIOD BIGINT
	,AVG_MTD_ACTL NUMERIC(25,2)
)
GO

INSERT INTO tryqw VALUES
(201501,      19833568.74),
(201502,      20545226.37),
(201503,      20207922.27),
(201504,      20275581.84),
(201505,      20220454.21),
(201506,      20213055.00),
(201507,      20232099.51),
(201508,      20250648.82),
(201509,      20248825.95),
(201510,      20224476.03),
(201511,      19905864.93),
(201512,      20503382.87)
GO

;WITH CTE AS
(
       SELECT * , DATEFROMPARTS( LEFT(PERIOD,4) ,  RIGHT(PERIOD,2) , '01' ) dt FROM tryqw
)
,CTE1 AS
(
       SELECT a.PERIOD , a.AVG_MTD_ACTL , ISNULL(qw.MonthySumChange,0) MonthySumChange FROM CTE a	  
       CROSS APPLY
       (
             SELECT SUM(b.AVG_MTD_ACTL) MonthySumChange 
             FROM CTE b
             WHERE b.dt = DATEADD(M,-11,a.dt)
       )qw
	   
)
SELECT * FROM CTE1

--

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0
 
Vitor MontalvãoMSSQL Senior EngineerCommented:
Since the period is by year and you have YYYYMM a good trick is to cast it to int and compare with the previous year so you can have the balance result:
SELECT t2.PERIOD, t2.AVG_MTD_ACTL-t1.AVG_MTD_ACTL Balance
FROM tblName t1
	INNER JOIN tblName t2 ON CAST(T2.PERIOD AS INT)-1=CAST(t1.PERIOD AS INT)

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0
 
Scott PletcherSenior DBACommented:
Which version of SQL Server?  In particular, SQL 2012 and later or before SQL 2012?
0
 
saved4useAuthor Commented:
SQL 2008.
0
 
Scott PletcherSenior DBACommented:
What result do you want to see for, say, the first three rows?

PERIOD      AVG_MTD_ACTL  ?monthly change in balance?
201501      $19,833,568.74   ?
201502      $20,545,226.37   ?
201503      $20,207,922.27   ?
0
 
saved4useAuthor Commented:
The balance difference between 201502 and 201501, followed by the difference between 201503 and 201502 and so forth. Basically the monthly increase/decrease spit out in another column.
Thank you.
0
 
Scott PletcherSenior DBACommented:
SELECT t.PERIOD, t.AVG_MTD_ACTL, t.AVG_MTD_ACTL - t_previous.AVG_MTD_ACTL
FROM tryqw t
LEFT OUTER JOIN tryqw t_previous ON t_previous.PERIOD = t.PERIOD - 1
0
 
Pawan KumarDatabase ExpertCommented:
Here is the entire code you need

CREATE TABLE tryqw
(
	 PERIOD BIGINT
	,AVG_MTD_ACTL NUMERIC(25,2)
)
GO

INSERT INTO tryqw VALUES
(201501,      19833568.74),
(201502,      20545226.37),
(201503,      20207922.27),
(201504,      20275581.84),
(201505,      20220454.21),
(201506,      20213055.00),
(201507,      20232099.51),
(201508,      20250648.82),
(201509,      20248825.95),
(201510,      20224476.03),
(201511,      19905864.93),
(201512,      20503382.87)
GO

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Solution

--


;WITH CTE AS
(
       SELECT * , DATEFROMPARTS( LEFT(PERIOD,4) ,  RIGHT(PERIOD,2) , '01' ) dt FROM tryqw
)
,CTE1 AS
(
      SELECT a.PERIOD , a.AVG_MTD_ACTL ,  a.AVG_MTD_ACTL - ISNULL(LAG(AVG_MTD_ACTL) OVER (ORDER BY dt), AVG_MTD_ACTL) Differences FROM CTE a	        
)
SELECT * FROM CTE1

--

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OUPTUT

Output..
Enjoy !!
1
 
Vitor MontalvãoMSSQL Senior EngineerCommented:
saved4use, can you at least give a feedback on the solutions that the Experts gave?
If not working please let us know the error for further investigation.
Cheers
0
 
saved4useAuthor Commented:
@Pawan, your last solution is close to perfect. However, can it be optimized for SQL Server 2008? Apparently, functions like LAG and DATEFROMPARTS are compatible with SQL Server 2012/16?
Thank you for your tremendous assistance.

"Msg 195, Level 15, State 10, Line 3
'LAG' is not a recognized built-in function name."
0
 
saved4useAuthor Commented:
Excellent and perfect! Thank you!
0
 
saved4useAuthor Commented:
@Pawan

How do I modify the above code snippet to make a table or select the average of the Differences column?
I have tried the below and keep getting the following error prompts:

Msg 102, Level 15, State 1, Line 3
Incorrect syntax near ';'.
Msg 102, Level 15, State 1, Line 14
Incorrect syntax near ')'.

select avg(Differences) as Avg_Diff

from (;WITH CTE AS
(
       SELECT * , CAST( (LEFT(PERIOD,4) +  RIGHT(PERIOD,2) + '01') AS DATE ) dt FROM tryqw
)
SELECT a.PERIOD , a.AVG_MTD_ACTL, a.AVG_MTD_ACTL - ISNULL(bn,a.AVG_MTD_ACTL) Differences FROM CTE a
OUTER APPLY
(
      SELECT TOP 1 b.AVG_MTD_ACTL bn
        FROM CTE b      
        WHERE a.dt > b.dt
        ORDER BY b.dt DESC
)t)

Thank you for your tremendous assistance.
0
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