Solved

# SQL for monthly balance change

Posted on 2016-10-06
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Working with a table that has a data as shown below. How do I write a T-SQL statement that shows the monthly change in balance over 12 consecutive months? Thanks.

PERIOD      AVG_MTD_ACTL
201501      \$19,833,568.74
201502      \$20,545,226.37
201503      \$20,207,922.27
201504      \$20,275,581.84
201505      \$20,220,454.21
201506      \$20,213,055.00
201507      \$20,232,099.51
201508      \$20,250,648.82
201509      \$20,248,825.95
201510      \$20,224,476.03
201511      \$19,905,864.93
201512      \$20,503,382.87
0
Question by:saved4use
• 5
• 4
• 3
• +2

LVL 35

Expert Comment

ID: 41832844
Do you mean a single dollar value that is the difference between a given month and a year before that?
0

LVL 28

Expert Comment

ID: 41832845
Hi,

Pls try this... If you need something different , please provide output expected. Thanks

``````--

CREATE TABLE tryqw
(
PERIOD BIGINT
,AVG_MTD_ACTL NUMERIC(25,2)
)
GO

INSERT INTO tryqw VALUES
(201501,      19833568.74),
(201502,      20545226.37),
(201503,      20207922.27),
(201504,      20275581.84),
(201505,      20220454.21),
(201506,      20213055.00),
(201507,      20232099.51),
(201508,      20250648.82),
(201509,      20248825.95),
(201510,      20224476.03),
(201511,      19905864.93),
(201512,      20503382.87)
GO

;WITH CTE AS
(
SELECT * , DATEFROMPARTS( LEFT(PERIOD,4) ,  RIGHT(PERIOD,2) , '01' ) dt FROM tryqw
)
,CTE1 AS
(
SELECT a.PERIOD , a.AVG_MTD_ACTL , ISNULL(qw.MonthySumChange,0) MonthySumChange FROM CTE a
CROSS APPLY
(
SELECT SUM(b.AVG_MTD_ACTL) MonthySumChange
FROM CTE b
)qw

)
SELECT * FROM CTE1

--
``````
0

LVL 28

Expert Comment

ID: 41832901
Or may be you need this.

``````--

CREATE TABLE tryqw
(
PERIOD BIGINT
,AVG_MTD_ACTL NUMERIC(25,2)
)
GO

INSERT INTO tryqw VALUES
(201501,      19833568.74),
(201502,      20545226.37),
(201503,      20207922.27),
(201504,      20275581.84),
(201505,      20220454.21),
(201506,      20213055.00),
(201507,      20232099.51),
(201508,      20250648.82),
(201509,      20248825.95),
(201510,      20224476.03),
(201511,      19905864.93),
(201512,      20503382.87)
GO

;WITH CTE AS
(
SELECT * , DATEFROMPARTS( LEFT(PERIOD,4) ,  RIGHT(PERIOD,2) , '01' ) dt FROM tryqw
)
,CTE1 AS
(
SELECT a.PERIOD , a.AVG_MTD_ACTL , ISNULL(qw.MonthySumChange,0) MonthySumChange FROM CTE a
CROSS APPLY
(
SELECT SUM(b.AVG_MTD_ACTL) MonthySumChange
FROM CTE b
)qw

)
SELECT * FROM CTE1

--
``````
0

LVL 47

Expert Comment

ID: 41833496
Since the period is by year and you have YYYYMM a good trick is to cast it to int and compare with the previous year so you can have the balance result:
``````SELECT t2.PERIOD, t2.AVG_MTD_ACTL-t1.AVG_MTD_ACTL Balance
FROM tblName t1
INNER JOIN tblName t2 ON CAST(T2.PERIOD AS INT)-1=CAST(t1.PERIOD AS INT)
``````
0

LVL 69

Expert Comment

ID: 41834098
Which version of SQL Server?  In particular, SQL 2012 and later or before SQL 2012?
0

Author Comment

ID: 41834171
SQL 2008.
0

LVL 69

Expert Comment

ID: 41834207
What result do you want to see for, say, the first three rows?

PERIOD      AVG_MTD_ACTL  ?monthly change in balance?
201501      \$19,833,568.74   ?
201502      \$20,545,226.37   ?
201503      \$20,207,922.27   ?
0

Author Comment

ID: 41834302
The balance difference between 201502 and 201501, followed by the difference between 201503 and 201502 and so forth. Basically the monthly increase/decrease spit out in another column.
Thank you.
0

LVL 69

Expert Comment

ID: 41834344
SELECT t.PERIOD, t.AVG_MTD_ACTL, t.AVG_MTD_ACTL - t_previous.AVG_MTD_ACTL
FROM tryqw t
LEFT OUTER JOIN tryqw t_previous ON t_previous.PERIOD = t.PERIOD - 1
0

LVL 28

Expert Comment

ID: 41834562
Here is the entire code you need

``````CREATE TABLE tryqw
(
PERIOD BIGINT
,AVG_MTD_ACTL NUMERIC(25,2)
)
GO

INSERT INTO tryqw VALUES
(201501,      19833568.74),
(201502,      20545226.37),
(201503,      20207922.27),
(201504,      20275581.84),
(201505,      20220454.21),
(201506,      20213055.00),
(201507,      20232099.51),
(201508,      20250648.82),
(201509,      20248825.95),
(201510,      20224476.03),
(201511,      19905864.93),
(201512,      20503382.87)
GO
``````

Solution

``````--

;WITH CTE AS
(
SELECT * , DATEFROMPARTS( LEFT(PERIOD,4) ,  RIGHT(PERIOD,2) , '01' ) dt FROM tryqw
)
,CTE1 AS
(
SELECT a.PERIOD , a.AVG_MTD_ACTL ,  a.AVG_MTD_ACTL - ISNULL(LAG(AVG_MTD_ACTL) OVER (ORDER BY dt), AVG_MTD_ACTL) Differences FROM CTE a
)
SELECT * FROM CTE1

--
``````

OUPTUT

Enjoy !!
1

LVL 47

Expert Comment

ID: 41836449
saved4use, can you at least give a feedback on the solutions that the Experts gave?
If not working please let us know the error for further investigation.
Cheers
0

Author Comment

ID: 41839214
@Pawan, your last solution is close to perfect. However, can it be optimized for SQL Server 2008? Apparently, functions like LAG and DATEFROMPARTS are compatible with SQL Server 2012/16?
Thank you for your tremendous assistance.

"Msg 195, Level 15, State 10, Line 3
'LAG' is not a recognized built-in function name."
0

LVL 28

Accepted Solution

Pawan Kumar earned 500 total points
ID: 41839543
Pls try this.. I

``````--

;WITH CTE AS
(
SELECT * , CAST( (LEFT(PERIOD,4) +  RIGHT(PERIOD,2) + '01') AS DATE ) dt FROM tryqw
)
SELECT a.PERIOD , a.AVG_MTD_ACTL, a.AVG_MTD_ACTL - ISNULL(bn,a.AVG_MTD_ACTL) Differences FROM CTE a
OUTER APPLY
(
SELECT TOP 1 b.AVG_MTD_ACTL bn
FROM CTE b
WHERE a.dt > b.dt
ORDER BY b.dt DESC
)t

--
``````
1

Author Closing Comment

ID: 41842639
Excellent and perfect! Thank you!
0

Author Comment

ID: 41851191
@Pawan

How do I modify the above code snippet to make a table or select the average of the Differences column?
I have tried the below and keep getting the following error prompts:

Msg 102, Level 15, State 1, Line 3
Incorrect syntax near ';'.
Msg 102, Level 15, State 1, Line 14
Incorrect syntax near ')'.

select avg(Differences) as Avg_Diff

from (;WITH CTE AS
(
SELECT * , CAST( (LEFT(PERIOD,4) +  RIGHT(PERIOD,2) + '01') AS DATE ) dt FROM tryqw
)
SELECT a.PERIOD , a.AVG_MTD_ACTL, a.AVG_MTD_ACTL - ISNULL(bn,a.AVG_MTD_ACTL) Differences FROM CTE a
OUTER APPLY
(
SELECT TOP 1 b.AVG_MTD_ACTL bn
FROM CTE b
WHERE a.dt > b.dt
ORDER BY b.dt DESC
)t)

Thank you for your tremendous assistance.
0

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