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An unhandled exception of type 'System.FormatException' occurred in mscorlib.dll

Posted on 2016-10-07
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Last Modified: 2016-10-07
private void TxtMarks1030_TextChanged(object sender, EventArgs e)
        {

            Int32 marks1030 = Convert.ToInt32(TxtMarks1030.Text);

            if (marks1030 >= 101)
            {
                LblGrade1030.Text = "Please enter less than 100";
            }
            else if (marks1030 >= 90)
            {
                LblGrade1030.Text = "A";
            }
            else if (marks1030 >= 80)
            {
                LblGrade1030.Text = "B";
            }
            else if (marks1030 >= 65)
            {
                LblGrade1030.Text = "C";
            }
            else if (marks1030 >= 50)
            {
                LblGrade1030.Text = "D";
            }
            else if (marks1030 >= 40)
            {
                LblGrade1030.Text = "E";
            }
            else
            {
                LblGrade1030.Text = "Fail";
            }
        }
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Question by:the student
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  • 2
5 Comments
 
LVL 33

Accepted Solution

by:
it_saige earned 500 total points
ID: 41834431
This exception occurs because the string being presented to convert is not convertable to an integer; e.g -
using System;

namespace EE_Q28975134
{
	class Program
	{
		static string grade1 = "90";
		static string grade2 = "I am not the number 90";

		static void Main(string[] args)
		{
			GetGrade(grade1);
			Console.WriteLine();
			GetGrade(grade2);
			Console.ReadLine();
		}

		private static void GetGrade(string value)
		{
			try 
			{
				int grade = Convert.ToInt32(value);
				if (grade > 100)
					Console.WriteLine("Please enter a grade less than 100.");
				else
					Console.WriteLine("Your test score - [{0}] produces a grade of: {1}", value, grade >= 90 ? "A" : grade >= 80 ? "B" : grade >= 65 ? "C" : grade >= 50 ? "D" : grade >= 40 ? "D" : "F");
			}
			catch (Exception ex)
			{
				Console.WriteLine("The value entered cannot convert to an integer, grade cannot be calculated.  {0}", ex.Message);
			}
		}
	}
}

Open in new window

Produces the following output -Capture.JPG
To correct you can use a try...catch block as I demonstrated:
private void TxtMarks1030_TextChanged(object sender, EventArgs e)
{
	try
	{
		Int32 marks1030 = Convert.ToInt32(TxtMarks1030.Text);
		if (marks1030 >= 101)
			LblGrade1030.Text = "Please enter less than 100";
		else if (marks1030 >= 90)
			LblGrade1030.Text = "A";
		else if (marks1030 >= 80)
			LblGrade1030.Text = "B";
		else if (marks1030 >= 65)
			LblGrade1030.Text = "C";
		else if (marks1030 >= 50)
			LblGrade1030.Text = "D";
		else if (marks1030 >= 40)
			LblGrade1030.Text = "E";
		else
			LblGrade1030.Text = "Fail";
	}
	catch (Exception)
	{
		LblGrade1030.Text = "Cannot convert grade";
	}
}

Open in new window

Or you could use a different method to convert your field's value, a method that does not throw an exception.  Something like Int32.TryParse.  Since it returns a boolean value that siginifies the conversion was successful, you would change your method to do this:
private void TxtMarks1030_TextChanged(object sender, EventArgs e)
{
	Int32 marks1030;
	if(Int32.TryParse(TxtMarks1030.Text, out marks1030))
	{
		if (marks1030 >= 101)
			LblGrade1030.Text = "Please enter less than 100";
		else if (marks1030 >= 90)
			LblGrade1030.Text = "A";
		else if (marks1030 >= 80)
			LblGrade1030.Text = "B";
		else if (marks1030 >= 65)
			LblGrade1030.Text = "C";
		else if (marks1030 >= 50)
			LblGrade1030.Text = "D";
		else if (marks1030 >= 40)
			LblGrade1030.Text = "E";
		else
			LblGrade1030.Text = "Fail";
	}
	else
	{
		LblGrade1030.Text = "Cannot convert grade";
	}
}

Open in new window


Proof of concept rewriting the above example:
using System;

namespace EE_Q28975134
{
	class Program
	{
		static string grade1 = "90";
		static string grade2 = "I am not the number 90";

		static void Main(string[] args)
		{
			GetGrade(grade1);
			Console.WriteLine();
			GetGrade(grade2);
			Console.ReadLine();
		}

		private static void GetGrade(string value)
		{
			int grade;
			if (int.TryParse(value, out grade))
			{
				if (grade > 100)
					Console.WriteLine("Please enter a grade less than 100.");
				else
					Console.WriteLine("Your test score - [{0}] produces a grade of: {1}", value, grade >= 90 ? "A" : grade >= 80 ? "B" : grade >= 65 ? "C" : grade >= 50 ? "D" : grade >= 40 ? "D" : "F");
			}
			else
			{
				Console.WriteLine("The value entered cannot convert to an integer, grade cannot be calculated.");
			}
		}
	}
}

Open in new window

Now produces a very similar output (minus the exception message ofcourse) -Capture.JPG
-saige-
0
 

Author Comment

by:the student
ID: 41834444
Thank you, it_saige.

It was very helpful now it's working fine. You made my day. This was the part of assignment. thank you again
0
 
LVL 80

Expert Comment

by:David Johnson, CD, MVP
ID: 41834461
Test for null or empty string.and validated input.
 private void TxtMarks1030_TextChanged(object sender, EventArgs e)
        {
            
            if (string.IsNullOrEmpty(TxtMarks1030.Text) == false)
            {
                try
                {
                    Int32 marks1030 = Convert.ToInt32(TxtMarks1030.Text);
                    if (marks1030 >= 101) { LblGrade1030.Text = "Please enter less than 100"; }
                    else if (marks1030 >= 90) { LblGrade1030.Text = "A"; }
                    else if (marks1030 >= 80) { LblGrade1030.Text = "B"; }
                    else if (marks1030 >= 65) { LblGrade1030.Text = "C"; }
                    else if (marks1030 >= 50) { LblGrade1030.Text = "D"; }
                    else if (marks1030 >= 40) { LblGrade1030.Text = "E"; }
                    else { LblGrade1030.Text = "Fail"; }
                }
                catch {
                    LblGrade1030.Text = "You must enter an integer  from 0 to 100";
                }
            }
        }

Open in new window


Yet another method that uses tryparse
using System;
using System.Windows.Forms;

namespace WindowsFormsApplication2
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
            LblGrade1030.Text = "Enter an Integer from 0 to 100";
        }

        private void TxtMarks1030_TextChanged(object sender, EventArgs e)
        {
            Int32 marks1030;
            LblGrade1030.Text = "Enter an Integer from 0 to 100";
            if (int.TryParse(TxtMarks1030.Text, out marks1030))
            {

                if (marks1030 >= 101) { LblGrade1030.Text = "Please enter less than 100"; }
                else if (marks1030 >= 90) { LblGrade1030.Text = "A"; }
                else if (marks1030 >= 80) { LblGrade1030.Text = "B"; }
                else if (marks1030 >= 65) { LblGrade1030.Text = "C"; }
                else if (marks1030 >= 50) { LblGrade1030.Text = "D"; }
                else if (marks1030 >= 40) { LblGrade1030.Text = "E"; }
                else { LblGrade1030.Text = "Fail"; }
            }

        }
    }

}

Open in new window

0
 
LVL 80

Expert Comment

by:David Johnson, CD, MVP
ID: 41834462
Should have refreshed the page first
2
 

Author Comment

by:the student
ID: 41834467
Thanks David Johnson
0

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