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Need T-SQL Statement grouping households

I have the following data structure and I need a T-SQL that will produce  a list of "Households"

House Number        Name           Street
-----------------              --------------    ---------------------
127                             Joe               Main Street
127                             Jane             Main Street
127                            Betty             Main Street
127                            Lois               Main Street

150                            Irving            Main Street
150                            Ruth              Main Street

210                            Rene             Main Street
210                            Jill                  Main Street

62                              Fred              High  Street
62                              Bob               High Street

77                              Ethel             High Street
77                              Lucy              High Street
77                              Richard         High Street
77                              Vivian            High Street

62                               Gene            Low Street
62                               Edward        Low Street

 I need a T-SQL statement to know how many family households live on each street and produce this output

Street                  Households
--------------------    ------------------------
Main Street        3
High Street         2
Low Street          1
0
Charles Baldo
Asked:
Charles Baldo
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1 Solution
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
Give COUNT(DISTINCT..) a whirl..
SELECT Street, COUNT(DISTINCT [House Number]) as Households
FROM YourTable
GROUP BY Street
ORDER BY COUNT(DISTINCT [House Number]) DESC

Open in new window

0
 
Nakul VachhrajaniTechnical Architect, Capgemini IndiaCommented:
You can do a COUNT of DISTINCT values as below:

DECLARE @houseInventory TABLE (HouseNumber INT, 
                               Name VARCHAR(255), 
                               Street VARCHAR(255)
                              );

INSERT INTO @houseInventory (HouseNumber, Name, Street)
VALUES (127, 'Joe'    , 'Main Street'),
       (127, 'Jane'   , 'Main Street'),
       (127, 'Betty'  , 'Main Street'),
       (127, 'Lois'   , 'Main Street'),
       (150, 'Irving' , 'Main Street'),
       (150, 'Ruth'   , 'Main Street'),
       (210, 'Rene'   , 'Main Street'),
       (210, 'Jill'   , 'Main Street'),
       (62 , 'Fred'   , 'High Street'),
       (62 , 'Bob'    , 'High Street'),
       (77 , 'Ethel'  , 'High Street'),
       (77 , 'Lucy'   , 'High Street'),
       (77 , 'Richard', 'High Street'),
       (77 , 'Vivian' , 'High Street'),
       (62 , 'Gene'   , 'Low Street' ),
       (62 , 'Edward' , 'Low Street' );

SELECT hi.Street,
       COUNT(DISTINCT hi.HouseNumber) AS NumberOfHouseholds
FROM @houseInventory AS hi
GROUP BY hi.Street

/* RESULTS
Street        NumberOfHouseholds
------------- ------------------
High Street   2
Low Street    1
Main Street   3
*/

Open in new window


By the way, I trust the 2 spaces between "High" and "Street" on House #62 (Fred) are by accident. In my example, I have only used one space (i.e. "High Street" instead of "High  Street")
0
 
Nakul VachhrajaniTechnical Architect, Capgemini IndiaCommented:
Sorry, Jim. Didn't mean to overlap with your answer.
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Charles BaldoSoftware DeveloperAuthor Commented:
Thank you
0
 
Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
No prob.  Two minute difference is not a big deal, and it takes at least that long to get the test T-SQL going.

Thanks for the grade, good luck with your project.  
Jim
0
 
Charles BaldoSoftware DeveloperAuthor Commented:
Thank you both very much
0

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