Permutation and Combination

How to solve this equation?

c(8, 3) * c(8, 2) / c(16, 5) = 14/39 ≈ 0.36
Tommy AndersonAsked:
Who is Participating?

Improve company productivity with a Business Account.Sign Up

x
 
JohnConnect With a Mentor Business Consultant (Owner)Commented:
C(n,r) and P(n,r) are standard Combination and Permutation formulas. Look them up (Google or CRC Tables) and then solve the problem.
0
 
JohnBusiness Consultant (Owner)Commented:
There is a standard formula for C(n,r) combinations in your text book.

Apply the formula to each term above (yields a number) and then multiply and divide for the answer
0
 
Tommy AndersonAuthor Commented:
unfortunately after 30 years I just dont remember anything in maths.
0
What Kind of Coding Program is Right for You?

There are many ways to learn to code these days. From coding bootcamps like Flatiron School to online courses to totally free beginner resources. The best way to learn to code depends on many factors, but the most important one is you. See what course is best for you.

 
phoffricCommented:
Your previous question shows that you know how to compute C(n,r) and know how to get the right answer for half of the questions.
https://www.experts-exchange.com/questions/28975162/Probability-question.html
(question deleted by the author).
0
 
Tommy AndersonAuthor Commented:
I copied it from the blackboard in the class. I dont know that you guys will be that hard on this question.
0
 
Tommy AndersonAuthor Commented:
My 30 years old notes when I was in school. Just dont remember.
0
 
phoffricConnect With a Mentor Commented:
Your formula that you used in your deleted question is correct:
              n! 
C(n,r) = ------------
          (n-r)! r!

Open in new window

0
 
JohnBusiness Consultant (Owner)Commented:
Thanks. Remember to use Google or like reference for formulas as that will jog your memory. I have been out of school longer than you :)
0
Question has a verified solution.

Are you are experiencing a similar issue? Get a personalized answer when you ask a related question.

Have a better answer? Share it in a comment.

All Courses

From novice to tech pro — start learning today.