<div>
Have a look at the built-in <a href="https://docs.python.org/3/library/shutil.html" rel="ugc">shutil</a> module (stands for <i>shell utilities</i>).<br />
<br />
You will find copy() and copy2(), and copytree().
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<div>
@pepr I did this and it worked.<br />
<br />
Do you think it would be best to wild card for *.mdb or just leave the code as is?<br />
<br />

<pre><code class="code-10 nolinks" id="code-20-41837444-1"><span>import os</span>
<span>import shutil</span>
<span>os.chdir('C:\\') #Make sure you add your source and destination path below</span>
<span></span>
<span>dir_src = (&quot;C:\\source\\&quot;)</span>
<span>dir_dst = (&quot;C:\\destination\\&quot;)</span>
<span></span>
<span>for filename in os.listdir(dir_src):</span>
<span>    if filename.endswith('.mdb'):</span>
<span>        shutil.copy( dir_src + filename, dir_dst)</span>
<span>    print(filename)</span>
</code></pre>
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<div>
It depends. Firstly, the line 3 does nothing for the purpose. The lines 5 and 6 should not use parentheses, and probably should use single quotes (for consistency). The <b>glob</b> module allows you to work with the mask directly. Anyway, I recommend to get used to os.path.join() function. It solves all problems with missing/extra (back)slashes in the path.<br />
<br />
Get used to normal slashes. One day, you may want to move your code to UNIX-based OS, and it will be easier. You get nothing when using backslashes. For print, use os.path.normpath() if you are picky.<br />
<br />
If you want to copy also the last modification time... use copy2().<br />
<br />
Print filename usually before the operation. When it crashes, you will know for what file.<br />
<br />

<pre><code class="code-10 nolinks" id="code-20-41837491-1"><span>#!python3</span>
<span></span>
<span>import glob</span>
<span>import os</span>
<span>import shutil</span>
<span></span>
<span>dir_src = 'C:/source'</span>
<span>dir_dst = 'C:/destination'</span>
<span></span>
<span>for filename in glob.iglob(os.path.join(dir_src, '*.mdb')):</span>
<span>    print(filename)</span>
<span>    shutil.copy(filename, dir_dst)</span>
</code></pre>
If you need to construct both paths (source and destination), then probably os.listdir() with os.path.join() is better.
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<div>
If you provide us a better description of the final tool you plan to build maybe we can point you in the right direction
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<div>
@pepr if I want to move files in a directory to a different destination after this copy has been done how would this be done?<br />
<br />
example: c:\source and c:\dest<br />
<br />
copy gets done first &gt;&nbsp;program action &gt;&nbsp;then move files in c:\dest to c:\dest_final?
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<div>
essentially i want to move and delete from source folder
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<div>
<div class="content wysiwyg-content">
Hello Experts- <br />
<br />
I am trying to copy a files in one directory source to destination directory.<br />
<br />
ex: copy and overwrite all files in c:\source to c:\destination<br />
<br />
What is the easiest way to do this?
</div>
</div>


Hello Experts- 

I am trying to copy a files in one directory source to destination directory.

ex: copy and overwrite all files in c:\source to c:\destination

What is the easiest way to do this?

Copy Files - Python

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Python

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