1-sum of the angles of a triangle = 180° = ACB+CAB+ABC

2-two angles are supplementary if the sum of their angles equals 180° = ACB + ECB = ABC+DBC

3-the bisectors of an angle divides the angle int 2 equal parts

this is sufficient information to solve for angles ECB, DBC, ICB, IBC and BIC

2-two angles are supplementary if the sum of their angles equals 180° = ACB + ECB = ABC+DBC

3-the bisectors of an angle divides the angle int 2 equal parts

this is sufficient information to solve for angles ECB, DBC, ICB, IBC and BIC