SQL Syntax: How to Find Commonality Among Similar Results

Hello:

Below is my code.  After it is a screenshot.

I want only rows 10 - 18.  As you can see, the difference between these rows and the others is that you have more than one "DocumentNumber".  Yet, you have only one "APTODCNM".

Specifically, for rows 10 - 18, I want the "Cnt" value to say 1, and the other rows to say "0".

I mean no offense, by this next request.  But, I don't want to hear anybody ask for sample data.  

This is a simple SQL syntax question.  That's all.  No background is required.  I know that you solid SQL coding gurus out there can solve this in your sleep.  Perhaps, it's simply a matter of adjusting the "HAVING...COUNT" syntax at the end of my query.

I look forward to hearing back on this, when I arrive in the office tomorrow.

Have a great night!

John

DECLARE @AGE DATETIME;
DECLARE @RUN DATETIME;
SET @AGE = '2015-09-30 00:00:00.000';
SET @RUN = '2016-07-31 00:00:00.000';

select RM20101.CUSTNMBR as [CustomerID], RM00101.CUSTNAME as [CustomerName], RM20101.DOCNUMBR as [DocumentNumber],
COUNT(*) OVER (PARTITION BY RM20201.APFRDCNM, RM20201.APTODCNM) AS Cnt, 
RM20201.APTODCNM, RM20201.DATE1, RM20101.GLPOSTDT, RM20101.DUEDATE, RM20101.DINVPDOF,
CASE WHEN 
RM20101.RMDTYPAL > 6 and RM20201.DATE1 > @AGE and RM20201.APFRDCDT > @AGE AND (RM20101.ORTRXAMT = RM20201.APPTOAMT)
and RM20201.APTODCDT = @AGE and RM20101.ORTRXAMT <> RM20101.CURTRXAM
THEN RM20201.APPTOAMT ELSE 0 END
as [OPEN A/R]
from RM20101
INNER JOIN RM00101 on RM20101.CUSTNMBR = RM00101.CUSTNMBR
INNER JOIN RM20201 on RM20101.DOCNUMBR = RM20201.APFRDCNM 
AND RM20101.CUSTNMBR = RM20201.CUSTNMBR
LEFT OUTER JOIN CN00500 ON RM20101.CUSTNMBR = CN00500.CUSTNMBR
WHERE (RM20101.VOIDSTTS = 0) and (RM20101.CUSTNMBR IN (' 320651', '00065', '00351', '00370', '0035829', '0015200', '0100010149', '0100011881', '0100011303', '0100011766', '0100012897',
'195145', '0100550714', '238624', '0100013309', '0100010453', '266267', '179520', '0100012517', '0100011519', '0100012160',
'0100012558', '0100075597', '0100075290', '0100354828', '274173', '0100014190', '0100020981', '00144', '0100015049', '0100014968', '0100018654', '0100019363', '0100019371',
'0100020932'))    
GROUP BY RM20101.CUSTNMBR, RM00101.CUSTNAME, 
RM20201.APTODCDT, RM20101.DOCNUMBR, 
RM20101.RMDTYPAL, RM20201.DATE1, RM20101.ORTRXAMT, RM20101.CURTRXAM, RM20201.APPTOAMT, RM20201.APFRDCNM, RM20201.APFRDCDT,
RM20201.APTODCNM, RM20101.GLPOSTDT, RM20101.DUEDATE, RM20101.DINVPDOF
--, RM20101.DOCDATE,
HAVING COUNT(RM20201.APFRDCNM) = 1 AND COUNT(RM20201.APTODCNM) = 1 AND
CASE WHEN 
RM20101.RMDTYPAL > 6 and RM20201.DATE1 > @AGE and RM20201.APFRDCDT > @AGE AND (RM20101.ORTRXAMT = RM20201.APPTOAMT)
and RM20201.APTODCDT = @AGE and RM20101.ORTRXAMT <> RM20101.CURTRXAM
THEN RM20201.APPTOAMT ELSE 0 END
<> 0

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